Q1. In this question, there is a certain relation between two given words on one side of:: and one word is given on another side of:: while another word is to be found from the given alternatives, having the same relation with this word as the words of the given pair bear. Choose the best alternative
Good : Bad : : Virtue : ?
Sol. The words in each pair are opposites of each other.
Q2. In this question, choose that set of numbers from the four alternative sets, that is similar to the given set (21, 51, 15)
(a) (21, 30, 51)
(b) (21, 35, 41)
(c) (21, 51, 42)
(d) (21,91, 35)
Sol. In each set . (3rd number × 2 ) + lst number = 2nd number.
Q3. In this question, four words have been given, out of which three are alike in some manner and the fourth one is different. Choose out the odd one.
Sol. All except Universe form a part of the universe
Q4. In this question, a number series is given with one term missing. Choose the correct alternative that will continue the same pattern and fill in the blank spaces.
0.5, 1.5, 4.5, 13.5, ( )
Sol. Each term of the series is obtained by multiplying the preceding term by 3.
Missing number = 13.5 x 3 = 40.5
Q5. In this question, one term in the number series is wrong. Find out the wrong term.
8, 13, 21, 32, 47, 63, 83
Sol. The sequence is + 5, + 8, +11, +14, +17, +20
So. 47 is wrong and must be replaced by (32 + 14) i.e. 46.
Q6. In this letter series some of the letters are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.
x _ az _ y _ zx _ c _
Sol. The series is xyaz/xybz/xycz
Q7. If POND is coded as RSTL, how is HEAR written in that code?
Sol. The first, second, third and fourth letters of the word are respectively moved two, four, six and eight letters forward to obtain the code.
Q8. If eraser is called box, box is called pencil, pencil is called sharpener and sharpener is called bag, what will a child write with?
Sol. The child will write with a ‘pencil’ and ‘pencil’ is called ‘sharpener’. So, the child will write with a ‘sharpener’.
Q9. In a certain code language, ‘381’ means ‘Hari is honest’-, ‘162’ means ‘Shashi is intelligent’ and ‘948′ means ‘Hari should go’. Which digit in that language means ‘honest’ ?
‘381’ ->’Hari is honest’ ………(i)
‘162’ -> ‘Shashi is intelligent’ ……(ii)
‘948′ -> ‘Hari should go’ ……(iii)
In (i) and (ii), the common code digit is ‘1’ and the common word is ‘is’.
In (i) and (iii), the common code digit is ‘8’ and the common word is ‘Hari’.
Thus, in (i), ‘3′ means ‘honest’.
Q10. Introducing a man to her husband, a woman said, “his brother’s father is the only son of my grandfather.” How is the woman related to his man ?
Sol. Only son of her grandfather — Her father;
man’s brother’s father — man’s father.
So, man’s father is her father i.e.. She is the man’s sister.
Q11. Dev walks 20 m towards North. He then turns left and walks 40 m. He again turns left and walks 20 m. Further, he moves 20 m after turning to the right. How far is he from his original position?
(a) 20 m
(b) 30 m
(c) 50 m
(d) 60 m
Q12. The number of boys in a class is three times the number of girls. Which one of the following numbers cannot represent the total number of children in the class?
(a) 48 ‘
Sol. Let number of girls = x and number of boys = 3x.
Then, 3x + x = 4x , total number of students.
Thus, to find exact value of x, the total number of students must be divisible by 4.
All sparrows are koels.
No koel is parrot.
I. No sparrow is parrot.
II. Some sparrows are parrots
III. All koels are sparrows.
IV. Some parrots are sparrows.
(a) Only I follows
(b) None follows
(c) Only II and III follow
(d) Only II and IV follow
Q14. Arrange the following items from general to particular:
Q15. In this question, different letters carries symbols as indicated below:
R : Addition S : Subtraction T: Multiplication
U: Division V: Equal to W : Greater than
X: Less than
Out of the four alternatives given in these questions, only one is correct according to the above letter symbols. Identify the correct one.
(a) 24 U 3 R 2 S 2 W 8
(b) 24 R 3 S 2 X 2 T 8
(c) 24 S 3 X 2 T 2 U 8
(d) 24 U 3 T 2 V 2 T 8
Sol. 24 U 3 T 2 V 2 T 8
24 ÷ 3 × 2 = 2 × 8
8 × 2 = 16