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The Railway Recruitment Board conducts the Non-Technical Popular Categories (NTPC) recruitment examination for graduate- and undergraduate-level positions. The selection process includes the 1st Stage Computer Based Test (CBT), 2nd Stage Computer Based Test (CBT), Typing Skill Test/Computer-Based Aptitude Test, and finally Document Verification/Medical Examination. Candidates appearing for CBT 1 and CBT 2 must keep themselves aware of the Mathematics questions which come for 30 marks for 30 questions.

For the ease of candidates and to enhance their preparation we are providing you with the Time and Distances Questions and Solutions for the RRB NTPC examination scheduled in the upcoming days. Start your journey of success with the questions mentioned below.

## RRB NTPC Time and Distances Questions

**Q1.** Two persons are traveling towards each other from point A and B. The distance between A and B is 50 km. It takes 8Hr to meet them. If the speed of a person traveling from A is 4 km/h then what will be the speed of another person?

(a) 1.75 km/h

(b) 2.5 km/h

(c) 1.50 km/h

(d) 2.25 km/h

**Q2.** Two cars are running on parallel tracks in the same direction at the speed of 50 km/h and 40 km/h respectively. The cars crossed each other in 3 minutes. If the length of one car in 175m then what is the length of the other car?

(a) 300 m

(b) 275 m

(c) 375 m

(d) 325 m

**Q3.** A wheel has a diameter of 42 cm, then how far does the wheel go (in meters) in 16 revolutions?

(a) 19 m

(b) 20.02 m

(c) 21.12 m

(d) 25 m

**Q4.** A person has to travel a distance of 80 km he finds that he has covered 58 of the distance in 3 hours and 20 minutes. What is his speed in km/h?

(a) 10 km/h.

(b) 12 km/h.

(c) 15 km/h.

(d) 13 km/h.

**Q5.** The distance between two places P and Q is 320km. A car runs from P to Q at a speed of 68km/h, while another car runs from Q to P at a speed of 72km/h. what will be the distance between the two cars (in km) 6 minutes before they meet?

(a) 14km

(b) 18km

(c)26km

(d)10km

**Q6.** Abhinav and Babita started their journeys from Delhi to Jaipur and Jaipur to Delhi, respectively. After crossing each other, Abhinav and Babita completed the remaining parts of their journeys in 945 hours and 5 hours, respectively. If the speed of Abhinav is 45 km/h, then the speed of Babita (in km/h) is:

(a) 65km/h.

(b) 56km/h.

(c) 61km/h.

(d) 63km/h

**Q7.** A wheel has a diameter 28 cm, then how far does the wheel go in 15 revolutions? Take π = 227

(a) 1000 cm

(b) 1100 cm

(c) 1200 cm

(d) 1320 cm

**Q8.** A person has to travel a distance of 60 km. he finds that he covered 53 of the distance in 3 hours 30 min. What is his speed for the distance he has covered?

(a) 1907 km/hr

(b) 2007 km/hr

(c) 3007 km/hr

(d) 2507 km/hr

**Q9.** Ravi drives his car for x km at a speed of 20 km/h and, for the next 180 minutes, he drives it at a speed of 10 km/h. If his average speed is 14 (in km/h) for the entire journey. Find the value of x.

(a) 42km

(b) 40km

(c) 45km

(d) 38km

**Q10.** A bus covers a distance of 455 km in 312 hours at a uniform speed. The time taken by the bus (in minutes) to cover a distance of 520 km at the same speed is:

(a) 180

(b) 240

(c) 360

(d) 300

**Q11.** A bus covers a distance of 455 km in 312 hours at a uniform speed. The time taken by the bus (in minutes) to cover a distance of 520 km at the same speed is:

(a) 180

(b) 240

(c) 360

(d) 300

**Q12.** While traveling from office to home, Ram’s car got some problem, so he took 16 23% more time than usual to reach home. His speed in this case is what percent less than his usual Speed?

(a) 16 23%

(b) 14 27%

(c) 5 56%

(d) 3 47%

**Q13.** A man covers a distance in 3hr 12min if he walks at the rate of 4km/hr. If he covers the same distance on a cycle at the rate of 24 km/hr, then the time taken by him in minutes is:

(a) 25 min

(b) 30 min

(c) 32 min

(d) 28 min

**Q14.** Two candles of the same length light up at the same time 1st candle ends in 4 hours and 2nd ends in 3 hours, rate of burning is different for both candles. After the start of burning, in how much time the ratio of their length will be 2: 1?

(a) 16 hours

(b) 14 hours

(c) 10 hours

(d) 12 hours

**Q15.** The distance between stations P and Q is 1360 km. Two persons A and B start their journey from P and Q respectively in the morning at 10 O’clock towards each other. The speed of B is 83.33% more than A. At the point of meeting, find the difference between the distance covered by them.

(a) 300 km

(b) 400 km

(c) 500 km

(d) 700 km

**Q16.** A bicycle wheel has a radius of 21 cm. It makes 20 revolutions in 20 seconds. What is its speed (in cm/s ) up to one decimal place?

(a) 132 cm/s

(b) 135 cm/s

(c) 138 cm/s

(d) 139 cm/s

**Q17.** A man cycles at the speed of 4 km/hr and reaches the office at 10:00 am and when he cycles at the speed of 6 km/hr, he reaches office at 8 am, At what speed should he cycle so that he reaches his office at 9:00 am?

(a) 9.6 km/hr

(b) 4.8 km/hr

(c) 5.7 km/hr

(d) 6.5 km/hr

**Q18.** A girl goes to her school at a speed of 6 km/hr and returns at the speed of 4 km/hr. If she takes 5 hours in all, then the distance (in km) between the village and the school is:

(a) 18km

(b) 10km

(c) 12km

(d) 13km

**Q19.** A train travels a 10.8 km distance in 25.5 minutes. Find its speed in meters/sec.

(a) 8.06m/sec.

(b) 5.07m/sec.

(c) 7.06 m/sec.

(d) 9.25m/sec.

**Q20.** A train run from Delhi at 9:00 am reached Jaipur at 11:00 am. Another train run from Jaipur at 9:00 am and reached Delhi at 12:00 pm. Find the meeting time.

(a) 10:12am

(b) 11am

(c) 10:20am

(d) 11:15am

## RRB NTPC Time and Distances Solutions

S1. Ans.(d)

Sol. Let, the speed of second persons = x km/h

then, (4 + x) = 50/8

⟹ x = 25/4 – 4 = 9/4 km/h=2.25k m/h

S6. Ans.(d)

Sol. Speed of Babita =?

Time taken by Abhinav after crossing = 495 hours

Speed of Abhinav = 45 km/h

Time taken by Babita = 5 hours

S7. Ans.(d)

Sol. Distance traveled by wheel in 15 revolutions = 2 × 227 × 14 × 15

⟹ 1320 cm

S14. Ans.(d)

Sol. Assuming the length of the candle = 12m

S18. Ans.(c)

Sol. Let the distance be d.

d/6+d/4 = 5

⟹ 5d/12 = 5

⟹ d = 12 km.