**Q1. A number is doubled and 6 is added to it. The resultant so obtained is multiplied by four, it becomes 96. What is the number? **

(a) 8

(b) 9

(c) 12

(d) 13

**S1. Ans.(b)**

**Sol.** Let the number = x

According to question,

4(2x + 6) = 96

2x + 6 = 24

⇒ x = 9

**Q2. When 1 is added to both the numerator and denominator of certain fraction it becomes half and when 1 is subtracted from both the numerator and denominator it becomes 1/3. Find the original fraction. **

(a) 5/9

(b) 4/9

(c) 4/7

(d) 3/7

**Q3. There is a vessel holding 40 litres of milk. Initially, 4 litres of milk is taken out form the vessel and 4 litres of water is poured in. After this, 5 litres of mixture is replaced with 5 litres of water. And finally, 6 litres of mixture is replaced with 6 litres of water. How much of the milk (in litres) is there in the vessel now? **

(a) 26.775

(b) 29.16

(c) 24.72

(d) 27.42

**S3. Ans.(a)**

**Sol. **Milk in a vessel = 40 litres

After first process

Milk =40×36/40 = 36 litres

Milk after the five litre of mixture replaced and water added =36×(1-5/40) =(36 × 35)/40

Milk after 6 litre of mixture replaced and water added =36×35/40×34/40

Now,

Quantity of Milk in vessel = 26.775

**Q4. Having scored 98 runs in the 19th inning, a cricketer increases his average score by 4. What will be his average score after 19 innings? **

(a) 28

(b) 26

(c) 24

(d) 22

**S4. Ans.(b)**

**Sol.** Let the average score of the 1st 18 innings be n

18 n + 98 = 19(n + 4) ⇒ n = 22

So, average score after 19th innings = x + 14 = 26.

**Q15. Left pan of a faulty balance weighs 100 grams more than its right pan. A shopkeeper keeps the weight measure in the left pan while buying goods but keeps it in the right pan while selling his goods. He uses only 1 kg weight measure. If he sells his goods at cost price, what is his gain percentage? **

(a) 200/11%

(b) 100/11%

(c) 1000/9%

(d) 200/9%

**S15. Ans.(d)**

**Sol.** Assume cp/1000 gm = Rs. 1000

He gets 1100 g for Rs. 1000 and

Sells 900 g for Rs. 1000.

So, cp/gram 1000/1100= Rs. 0.90/g

Sp/gram =1000/900 = Rs. 1.11/g

So, profit% =(1.11 – 0.90)/0.9×100

Hence, option (d) is the answer.

**Q6. Mohan bought 3 cows for Rs. 21,200. He sells all the three cows for Rs. 22,360. On the first cow, he makes a profit of Rs. 560 at 10% on cost price. On the second, he makes a profit of Rs. 1440 at 20% on cost price. Find the % profit of % loss made on the third cow. **

(a) 20% profit

(b) 20% loss

(c) 10% profit

(d) 10% loss

**S6. Ans.(d)**

**Sol.** CP of first cow = 560(100/10) = Rs. 5600

CP of second cow =1440(100/20)= Rs. 7200

⇒ CP of third cow = 21,200 – (5600 + 7200) = Rs. 8400

Now, total profit = Rs. (22,360 – 21,200) = Rs. 1160

⇒ Profit made on 3rd cow = 1160 – (560 + 1440) = -840

= Rs. 840 loss.

So, % loss =840/8400×100=10%

**Q7. A seller gives a discount of 20% on a pen and sells it at Rs. 960. Had he not given the discount, profit would have been 40%. If he wants to gains a profit of 54% on the cost price of watch, what should be selling price? **

(a) Rs. 1320

(b) Rs. 1400

(c) Rs. 1200

(d) Rs. 1280

**S7. Ans.(a) **

**Sol.** Mark price of pen =960/80=1200

C.P. of pen =1200/1.4

To gain a profit of 54% selling price =1200/1.4×1.54=1320

**Q8. A dishonest dealer professes to sell his goods at a profit of 20% and also uses weight 800 gm at the place of 1 kg. Find actual gain percentage. **

(a) 40%

(b) 45%

(c) 50%

(d) 60%

**S8. Ans.(c)**

**Sol.** Let the price of each gram goods is 1 Rs

Selling price of 1000 gm good = 1000 × 1.2 = 1200 Rs.

Cost price = 800 Rs.

Profit =((S.P.)/(C.P.)-1)×100 = 50%

**Q9. The ratio of the age of a man and his wife is 4 : 3. After 4 years, this ratio will be 9:7. If at the time of the marriage, the ratio was 5:3, then how many years ago they were married? **

(a) 12 years

(b) 8 years

(c) 10 years

(d) 15 years

**Q10. What least number must be subtracted from each of the numbers 14, 17, 34 and 42 so that the numbers left are proportional? **

(a) 0

(b) 1

(c) 2

(d) 7

**S10. Ans.(c)**

**Sol.** From the given option,

If we subtract 2 from each number, then number will become 12, 15, 32 and 40

⇒ 12/15=32/40

Hence, option (c) is a right option.

**Q11. A’s efficiency is 50% of efficiency of B and C together and efficiency of A and C is 19/8 times the efficiency of B. Ratio of efficiency of B and C is 4:5. If all of them working together complete the work in 13 1/3 days. In how many days B can do the work, working alone? **

(a) 45 days

(b) 50 days

(c) 30 days

(d) 50 days

**Q12. Two workers earned Rs. 225 first worked for 10 days and the second for 9 days. How much did each of them get daily if the first worker got Rs. 15 more for working 5 days than the second worker got for working 3 days? **

(a) Rs. 11.70, Rs. 12.00

(b) Rs. 10.80, Rs. 13.00

(c) Rs. 11.25, Rs. 12.50

(d) Rs. 12.60, Rs. 11.00

**S12. Ans.(b)**

**Sol.** Let A got Rs x per day and B got Rs y per day.

So, 10x + 9y = 225 and 5x = 3y + 15

⇒ x = 10.80, y = 13

**Q13. A boat travels downstream to cover a distance of 80 km in 5 hrs and upstream to cover a distance of 48 km in 8 h. Find the speed of boat in still water. **

(a) 11 km/h

(b) 12 km/h

(c) 14 km/h

(d) 16 km/h

**S13. Ans.(a)**

**Sol.** Downstream speed = 80/5 = 16 kmph = Speed of boat in still water + Speed of current

Upstream speed = 48/8 = 6 kmph = Speed of boat in still water – Speed of current

So, speed of boat in still water = (Downstream speed + Upstream speed)/2 = 11 kmph

**Q14. Forty per cent of employees of a certain company are man, and 75% of the men earn more than Rs. 25,000 per year. If 45% of the company’s employees earn more than Rs. 25,000 per year, what fraction of the women employed by the company earn less than or equal to Rs. 25,000 per year? **

(a) 2/11

(b) 1/4

(c) 1/3

(d) 3/4

**S14. Ans.(d)**

**Sol.** Men women

40% 60%

Out of 40% men, 75% earn more than Rs. 25,000. Hence, 30% of the company (men) earn more than Rs. 25,000.

But in all 45% of the employees earn more than Rs. 25,000.

Hence among women 15% earn more than Rs. 25,000 and the remaining (60 – 15) % earn less than or equal to Rs. 25,000.

Therefore, the fraction of women =45/60=3/4