Tricky questions of Reasoning for SSC CHSL & RRB NTPC


Direction (1-6): In each of the following question, a series is given with one term missing. Find out the missing term from the given alternatives.

Q1. 0, 6, 24, 60, 120, 210, ?
(a) 250
(b) 300
(c) 336
(d) 444

Q2. 4, 6, 12, 14, 28, 30, ?
(a) 32
(b) 60
(c) 62
(d) 64

Q3. 1, 3, 3, 6, 7, 9, ?, 12, 21
(a) 9
(b) 20
(c) 11
(d) 13

Q4. GH, JL, NQ, SW, YD, ?
(a) EG
(b) FJ
(c) HL
(d) FL

Q5. ajs, gpy, ?, sbk, yhq
(a) dmv
(b) mve
(c) oua
(d) qrv

Q6. AI, BJ, CK, ?
(a) DL
(b) DM
(c) JH
(d) LN

Direction (7-11):  In this question, there is some relationship between the two terms to the left of : : and the same relationship holds between the two terms to its right. Find out the missing term. 

Q7. Lion : Deer :: Mongoose : ?
(a) Rat
(b) Snake
(c) Lizard
(d) Squirrel

Q8. Moth : Insect :: Mouse : ?
(a) Cat
(b) Mole
(c) Rodent
(d) Rat

Q9. Plant : Tree :: Girl : ?
(a) Wife
(b) Mother
(c) Woman
(d) Sister

Q10. Clock : Time :: Thermometer : ?
(a) Heat
(b) Radiation
(c) Energy
(d) Temperature

Q11. Muslims : Mosque :: Sikhs : ?
(a) Golden Temple 
(b) Medina
(c) Fire Temple
(d) Gurudwara

Directions (12-15): In each of the questions below, a group of numerals is given followed by four groups of symbol/letter combinations labelled (a), (b), (c) and (d). Numerals are to be coded as per the codes and conditions given below. You have to find out which of the combinations (a), (b), (c) and (d) is correct and indicate your answer accordingly. 
Numerals
3
5
7
4
2
6
8
1
0
9
Letter/Symbol
code
*
B
E
A
@
F
K
%
R
M
Following conditions apply:
(i) If the first digit as well as the last digit is odd, both are to be coded as ‘X’.
(ii) If the first digit as well as the last digit is even, both are to be coded as ‘$’.
(iii) If the last digit is 0, it is to be coded as ‘#’.

Q12. 546839
(a) XAFK*M
(b) BAFK*M
(c) XAFK*X
(d) BAFK*X

Q13. 713540
(a) E%*BA#
(b) X%*BA#
(c) X%*BAR
(d) E%*BAR

Q14. 765082
(a) XFBRK@
(b) EFB#K@
(c) EFBR#K
(d) EFBRK@

Q15. 487692
(a) $KBFM$
(b) $KEBM$
(c) $KEFB$
(d) $KEFM$











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