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# Target SSC CGL | 10,000+ Questions | Reasoning Questions For SSC CGL : Day 141

This is the new year with new goals, new experiences and lots of exams to be scheduled soon. SSC CGL has recently released the exam dates so now it is time to gear up your preparations and try hard to get success. ADDA247 never fails to deliver something new and fruitful for you all. This time also we are providing you the best study plan as well as a study material. We are here going to prepare your Reasoning section for the SSC CGL. In this article, we are providing you the details that how we are going to help you to clear the examination this year. We ADDA247 is going to provide you daily tests for all the subjects. The topic-wise quiz will be done from January till May. This will help you to get a deeper knowledge of all the topics and will prepare you thoroughly.

Directions (1-2): In each of the following questions, find out which of the letter-series follows is the given rule.

Q1. Number of letters skipped in between adjacent letters in the series is two
(a) MPSVYBE
(b) QSVYZCF
(c) SVZCGJN
(d) ZCGKMPR

Q2.Number of letters skipped in between adjacent letters do not decrease in order.
(a) EQZFI
(b) GWIQU
(c) MGVFK
(d) PJXHM

Directions (3-5): Study the letter-series given below and answer the questions that/follow:
H D Y S M W N B Q P O C R T B L Z V E G U F

Q3. Which two neighbours in the given arrangement are farthest in the alphabetical order?
(a) B and Q
(b) D and Y
(c) U and F
(d) V and E

Q4. Which letter has the same neighbours as in the alphabetical order though they have changed places?
(a) M
(b) N
(c) O
(d) P

Q5. Which three letters have the same distance as they have in the alphabetical order though they have changed places?
(a) HMP
(b) NQZ
(c) QOE
(d) YLE

Directions (6-10): Letters of the words given below have been jumbled up. You are required to construct the words. Each letter has been numbered and each word is followed by four options. Choose the option which gives the correct order of the letters as indicated by the numbers to form words.

Q6.
T I R B H G
1 2 3 4 5 6
(a) 1, 3, 2, 4, 6, 5
(b) 3, 2, 6, 5, 4, 1
(c) 4, 3, 2, 6, 5, 1
(d) 4, 5, 2, 3, 6, 1

Q7.
N R O C T A
1 2 3 4 5 6
(a) 1, 6, 2, 4, 3, 5
(b) 2, 3, 5, 4, 6, 1
(c) 4, 6, 2, 5, 3, 1
(d) 6, 5, 2, 3, 1, 4

Q8.
K A T C E L
1 2 3 4 5 6
(a) 1, 2, 4, 5, 6, 3
(b) 3, 2, 4, 1, 6, 5
(c) 4, 2, 3, 1, 5, 6
(d) 6, 5, 3, 2, 4, 1

Q9.
R T A N U E
1 2 3 4 5 6
(a) 1, 3, 2, 6, 4, 5
(b) 3, 2, 4, 6, 1, 5
(c) 4, 3, 2, 5, 1, 6
(d) 4, 6, 5, 2, 3, 1

Q10.
N A E H L D
1 2 3 4 5 6
(a) 2, 1, 6, 4, 3, 5
(b) 2, 6, 4, 3, 5, 1
(c) 4, 2, 1, 6, 5, 3
(d) 4, 3, 6, 5, 2, 1

Solutions

S3. Ans.(b)
Sol. Clearly, D and Y are neighbours in the given series and are separated by the maximum number of letters i.e. 20 in the English alphabet.

S4. Ans.(d)
Sol. P has O and Q as its neighbours in the given series as well as in the English alphabet.

S5. Ans.(d)
Sol. There are 12 letters between L and Y and 5 letters between F and L in the given series as well as in the English alphabet.

S6. Ans.(c)
Sol. BRIGHT

S7. Ans.(c)
Sol. CARTON

S8. Ans.(b)
Sol. TACKLE

S9. Ans.(c)
Sol. NATURE

S10. Ans.(C)
Sol. HANDL

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