**Hello Readers,**

**We shall discuss about Percentage of the Quant section. Now a days these topics have became an important part of the Quant test in not only SSC but also almost in all Entrance Exams like FCI Exams and IBPS Exam.So Here we will help you in this.We will provide short tricks on Percentage with Quant Quiz.**

**Percentage:**A fraction whose denominator is 100 is called percentage. and The numerator of the fraction is called the rate percent.

**1**. To express x% as a fraction:

**2**. To express fraction as percentage,

**a/b = {a/b x100}%**

**3**. If A is R% more than B, then B is less than A by

**{(R/(100+R)x100}%**

**4**. If A is R% less than B, then B is more than A by

**{(R/(100-R)x100}%**

**5**. If the price of a commodity increases by R%, then the reduction in consumption so as not to increase the expenditure is:

**{(R/(100+R)x100}%**

**6**. If the price of a commodity decreases by R%, then the increase in consumption so as not to decrease the expenditure is:

**{(R/(100-R)x100}%**

**7**. Let the population of a town be P now and suppose it increases at the rate of R% per annum, then

**1. Population after n years**=

**P(1+R/100)^n**

**2.Population before n years**=

**P/(1 + R/100)^n**

**8**. Let the present value of a machine be P. Suppose it depreciates at the rate of R% per annum.

**1.Value of the machine after n years**=

**P(1-R/100)^n**

**2.Value of the machine n years ago**=

**P/(1-R/100)^n**

**9**. For two successive changes of x% and y%, net change

**{x + y +xy/100}%**

**1. A shopkeeper announces successive discounts of 10% and 20%. Find the equivalent percent discount.**

**2. In a college, 40% of the students were allotted group A, 75% of the remaining were given group B and the remaining 12 students were given group C. Then the number of students who applied for the groups is:**

**3.Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:**

**4. In a competitive examination in State A, 6% candidates got selected from the total appeared candidates. State B had an equal number of candidates appeared and 7% candidates got selected with 80 more candidates got selected than A. What was the number of candidates appeared from each State?**

**5. The price of a car is Rs. 3,25,000. It was insured to 85% of its price. The car was damaged completely in an accident and the insurance company paid 90% of the insurance. What was the difference between the price of the car and the amount received ?**

**6. Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?**

**7. In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is of the number of students of 8 years of age which is 48. What is the total number of students in the school?**

**8. A’s salary is 30% higher than B’s salary. The percent that B’s salary is less than A’s salary is:**

**9. If the price of sugar is increased by 25%, by how much percent must a householder reduce his consumption of sugar so as not to increase his expenditure on sugar?**

**10. In a class of 40 students and 8 teachers, each student got sweets that are 20% of the total number of students and each teacher got sweets that are 25% of the total number of students. How many sweets were there?**

D. 360

Answer and Solution :

1(B)Explanation

For two successive changes of x% and y%, net change =

{x + y +xy/100}%

= {-10-20+(-10)(-20)/100}%

=(-30 + 2) %

= – 28%

2(A)Explanation

Let the number of students be 100.

Number of students allotted to group A = 40

Number of students allotted to group B = 75% of 60 = 45

Thus, Balance number of students allotted to group C = 100 – 40 – 45 = 5

Number of actual students = 100/15 * 12 = 80

3(C)Explanation:

Let their marks be (x + 9) and x.

Then, x + 9 = 56/100(x + 9 + x)

=>25(x + 9) = 14(2x + 9)

=>3x = 99

=>x =33

So, their marks are 42 and 33.

4(D)Explanation :

State A and State B had an equal number of candidates appeared.

In state A, 6% candidates got selected from the total appeared candidates

In state B, 7% candidates got selected from the total appeared candidates

But in State B, 80 more candidates got selected than State A

From these, it is clear that 1% of the total appeared candidates in State B = 80

=> total appeared candidates in State B = 80 x 100 = 8000

=> total appeared candidates in State A = total appeared candidates in State B = 8000

5(A)Explanation :

Price of the car = Rs.3,25,000

Car insured to 85% of its price

=>Insured price=325000×85/100

Insurance company paid 90% of the insurance

Amount paid by Insurance company =Insured price×90/100

=325000×85/100×90/100=325×85×9=Rs.248625

Difference between the price of the car and the amount received

= Rs.325000 – Rs.248625 = Rs.76375

6(C)Explanation:

Let the amount taxable purchases be Rs. x.

Then, 6% of x = 30/100

=> x = (30/100 x 100/6) = 5

so Cost of tax free items = Rs. [25 – (5 + 0.30)] = Rs. 19.70

7(D)Explanation:

Let the number of students be x. Then,

Number of students above 8 years of age = (100 – 20)% of x = 80% of x.

so 80% of x = 48 + 2/3 of 48

=> 80/100 x = 80

=> x = 100.

8(C)Explanation:

Let B’s salary be Rs. 100

Then , A’s salary = Rs.130

Required percentage = 30/100 * 100 = 23 1/13%

9(D) Explanation:

If the price of a commdity increases by R% , then the reduction in consumption so as not to increase the expenditure is :

{(R/(100+R)x100}%

Thus, percent reduction in consumption = {(25/(100+25)x100}%

= 20 %

10(B)Explanation :

Number of students in the class = 40

Sweets received by 40 students = 40 * (20% of 40) = 320

Number of teachers in the class = 8

Sweets received by 8 teacher = 8 * (25% of 40) = 80

Total number of sweets = 320 + 80 = 400

Thanks for SA Team

thank uuuuuuuuuuuuu

thanks SA _/_

1- 22% hona chahiye na ?

Haa bhai…

option diya hi nhi

Ssc cgl me sari preference fill krna jaruri h kya?

b 28

Han….aapne kaha to hona hi chahiye :))

explain plz

can any1 help me The least multiple of 13 which on dividing by 4,5,6,7,8 leaves remainder 2 in each case? with explanation

28

ok dekhta hoon fir se

Plz example ist

ex :take 100

1st 10% discount so it must be (100-10=90)

2nd 20% discount so it becomes (90-18=72)

so total discount (100-72=28)

got it..

let x = 100

10 % discount so

remaining = 90

again 20% discount

that means 90- 18

= 72

equvalent discount = 100-72 = 28

Bhai (-20)+(-30)+((-20)×(-30)/100)=

= -28…:p

mtlb ?

option ??

Sorry 30 k jagah pe 10 he..

Matlab 1 st queatn explain Karna tha ji …ho gaya

ok thanks

shukriya 🙂

2522 is ans but m not getting it

han bhai samajh gye

Refresh

let M.P=100 then

MP*(Dis/100)*(Dis/100)=SP

100*(90/100)*(80/100)=72

Now 100-SP=28

take lcm of 4,5,6,7,8

that is 840

so (840K+2)

k ki vallue 1,2,3… put kro..or 13 se devide kro…

here k =3

840*3+2 = 2522

_/_

Which planet do u belongs to??

_/_

ok thanks bro :))

🙂

what ?? :P:P

always welcome bro…

abhi to..yhi hu 😀 😀

Nothing ,,means so fast 🙂

:))

Hihihi…

new to SA ?

8-c??

Kro.welcome shaandar :))

9.D..:P

yupp

hehe,, wohi soch rhe the :p

:))

25/100*100???

Pata nahi….:P

Bs sochtey mt rehna ,, :))

Bt ab pta chal.gya mujhe k.ye sahi hai

2- A 😀

25/125 *100

ok i got it tnq

Actually I need solutions too :))

Hihihihi..

ya for u i created id and login.

Arey han bhool gae 🙂

mne to option se kia 😛

i dont know hindi very well so plz tell me in telugu or english.

hum dhanya ho gye :))

#i hope u understand hindi

Oh…theek h no problem ..bt a aage se with solution 😀

Bt I am shocked :)) :))

hehe ..ok :))

y so

ohh no worries..

english should be just fine :))

:))

4– D 😛

No,,we were talking something else :)),welcm to SA

tnx

thnk u

5-A

:))

10-B

6-C

can anyone post the Discount formulas…. plz

7-c

1-B 2-A 3-C 4-D 5-A 6-C 7-D 8-C 9-D 10-BMaddali siva Reddy,,,,,rece gurram

10.B………:B

ya means thanks

8-D

sry 8-c

9-D

9-D

10 th explain

actually means,,

i'm grateful to u 🙂

10-B

6-c

Ho gaya maine kr liya

7th btao koi…………

ok..

8-c

4-d

okk 🙂

10-B

9-D

7th queatn me.kuch missing hai kya 3 line me ?

ques adhura lag rha hai

b,a,c,d,a

c,c,c,d,b

1-B

mujhe bhi

2nd line mai

2-B

Han kisi na kisi line me :))

Que 7In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is 2/3 of the number of students of 8 years of age which is 48. What is the total number of students in the school?Plz explain 6th

ab to bht easy h :P:P

100…perhaps!!

Pata nahi kaise sab incomplete question me complete ans kaha se laa dete he….:P

Ghar se :))

Right

(y)

Hehehe..

May b practise krte tym aaya ho questn pehle

Explain kr do glady

##

Ambassador or Norway and the phillipines killed in Pakistan helicopter crash

Kon sa??

Q.7

total student=x

20% of students are below 8 years of age

number of students above or equal to 8 years of age = 80% of x—-1

given number of students of 8 years of age = 48——-2

number of students above 8 years of age = (2/3)*48

number of students above 8 years of age =32——-3

frm eqn 1,2 and 3

80% of x=48+32

(4/5)*x= 80

x=100

6,7

Thanx shadow

🙂

6,5 and 7th mt krna

Refresh for answers!!!

thanks 🙂

6…

6% x= 0.30

X=0.30×100/6

X=5

Tax free item =25-0.30-5= 19.70

@Sayar bhai???

Reasoning Quiz On Dictionary

http://www.sscadda.com/2015/05/reasoning-quiz-on-dictionary.html

100

in 2Q 100/15 here 15 kaha se ayaaa.. ? plz explain…

best gk book for ssc cgl exam

pls reply friends

plz explain 6th que…..anyone..

Lucent

200-40-45=15

Let A does in a days a=10

B does in b days, b=15

Now time reqd to complete the work when B leaves 2 days (x)before completion= a(b+x)/(a+b)

= 10× (15+2)/(10+15)

=10×17/25

=34/5 days.

THANKS FRIEND

How that formula came ji…

The formula is as under

If A and B can finish a work in a and b days respectively and

(I) if A leaves x days before completion then time taken to complete the work= b(a+x)/(a+b) days and

(ii) if B leaves x days before comprtion then time taken to complete the work= a(b+x)/(a+b) days.

K thank u