SSC Maths Quiz

ANSWERS
 (1)A
 LCM of 3,4,5,6 and 8=120.Now,by seen the option we get that 14400 is a least five digit perfect square number which is divisible by 120

 (2)B
  it follows 1+4,next one 1+9,2+9 in same way 44+(4+4)=52 not 51

 (3)B
 given S.P of table =30 profit percentage = 20% CP of table =(30*90)/10 =27 required profit percentage = (27-25)/25 *100 =8%

 (4)C
 Here, a=10L, n=2 and x=100L
Quantitiy of wine in end =x(1-a/x)^n
                                        =100(1-10/100)^2
                                        =81L
 Required ratio =81:(100-81)=81:19

 (5)D
 Let the marks of A,B and C are 10x,12x and 15X respectively.
 maximum marks of C=15*6=90 and maximum marks of
 b=12*6=72 hence the marks of B cannot be in the range of (80-90)

 (6)B
 Let CP=Rs 1000
 Actual CP=Rs 920 and selling price =(1000*115)/100 = 1150
 Actual profit percentage = (1150-920)/920 * 100% =25% ans

 (7)D
 Perimeter of circular sheet = 2πr =20π cm
 The perimeter of base of conical surface = 20π*(100-40)/100 =12π
  Radius of base of conical surface = 12π/2π = 6cm
  & the height of conical surface =  √(10^2-6^2)=8cm
  so,The required ratio = 6:8 or 3:4

 (8)B
  x= sinθ+cosθ y= Secθ+cosecθ
    =1/sinθ+1/cosθ
    =sinθ+cosθ/sinθcosθ
    =x/sinθcosθ……..2
  (sinθ+cosθ)^2=1+2sinθcosθ
     x^2=1+2sinθcosθ
     sinθcosθ=(x^2-1)/2 from equation …..2
     y=2x/x^2-1 ans

(9)B
sinθ+cossecθ=2
sinθ+1/sinθ =2
sin^2θ+1=2 sinθ
(sin^2θ-2sinθ+1)=0
(sinθ-1)^2=0
sinθ=1=sin90°
θ = 90°
so,sin^7θ+cosec^7θ=1+1 =2ans

(10)A
 f(θ)=sin^8θ+cos^14θ
       =sin^8θ+(1-sin^2θ)^7
 f(90°)=1+(1-1)^7
           =1