**Dear Readers, Here We are providing a quant Quiz of 15 question in accordance with the syllabus of SSC CGL. These Questions cover the Advance Math.**

**Q1. Bhuvnesh has drawn an angle of measure 45°27 when he was asked to draw an angle of 45°. The percentage error in his drawing is**

(a) 0.5%

(b) 1.0%

(c) 1.5%

(d) 2.0%

**Q2.In a regular polygon, the exterior and interior angles are in the ratio 1 : 4. The number of sides of the polygon is**

(a) 5

(b) 10

(c) 3

(d) 8

**Q3. The sides of a triangle are in the ratio 3 : 4 : 6. The triangle is:**

(a) acute – angled

(b) right – angled

(c) obtuse – angled

(d) either acute – angled or right angled

**Q4. If the length of the three sides of a triangle are 6 cm, 8 cm and 10 cm, then the length of the median to its greatest side is**

(a) 8 cm

(b) 6 cm

(c) 5 cm

(d) 4.8 cm

**Q5. If the circumradius of an equilateral triangle be 10 cm, then the measure of its in-radius is**

(a) 5 cm

(b) 10 cm

(c) 20 cm

(d) 15 cm

**Q6. O and C are respectively the orthocentre and the circumradius of an acute-angled triangle PQR. The points P and O are joined and produced to meet the side QR at S. If ∠PQS = 60° and ∠QCR = 130°, then ∠RPS = ?**

(a) 30°

(b) 35°

(c) 100°

(d) 60°

**Q7. In ∆ABC, AD is the internal bisector of ∠A, meeting the side BC at D. If BD = 5 cm. BC = 7.5 cm, then AB : AC is**

(a) 2 : 1

(b) 1 : 2

(c) 4 : 5

(d) 3 : 5

**Q8. I is the incentre of ∆ABC, ∠ABC = 60° and ∠ACB = 50°. Then ∠BIC is**

(a) 55°

(b) 125°

(c) 70°

(d) 65°

**Q9.The in-radius of an equilateral triangle is of length 3 cm. Then the length of each of its medians is**

(a) 12 cm

(b) 9/2 cm

(c) 4 cm

(d) 9 cm

**Q10. Two medians AD and BE of ∆ABC intersect of G at right angles. If AD = 9 cm and BE = 6 cm, then the length of BD (in cm) is**

(a) 10

(b) 6

(c) 5

(d) 3

**Q11. The difference between the interior and exterior angle at a vertex of a regular polygon is 150°. The number of sides of the polygon is**

(a) 10

(b) 15

(c) 24

(d) 30

**Q12. Each interior angle of a regular polygon is 144°. The number of sides of the polygon is**

(a) 8

(b) 9

(c) 10

(d) 11

**Q13. If the sum of the interior angles of a regular polygon be 1080°, the number of sides of the polygon is**

(a) 6

(b) 8

(c) 10

(d) 12

**Q14. The number of sides in two regular polygons are in the ratio of 5 : 4. The difference between their Interior angles of the polygon is 6°. Then the number of sides are**

(a) 15, 12

(b) 5, 4

(c) 10, 8

(d) 20, 16

**Q15. Each internal angle of regular polygon is two times its external angle. Then, the number of sides of the polygon is:**

(a) 8

(b) 6

(c) 5

(d) 7