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SSC CGL Quantitative Aptitude : 11th February 2020 for Geometry and Coordinate Geometry

Q1. If ∠A = 44°, BP = BR and CN =RC then ∠PRN = ?
SSC CGL Quantitative Aptitude : 11th February 2020 for Geometry and Co- ordinate Geometry_50.1
(a) 58°
(b) 78°
(c) 68°
(d) 66°

Q2. In the given figure, AC ⊥ CE and ∠A : ∠B : ∠C = 3 : 2 : 1, find the value of ∠ECD :
SSC CGL Quantitative Aptitude : 11th February 2020 for Geometry and Co- ordinate Geometry_60.1
(a) 50°
(b) 45°
(c) 55°
(d) 60°

Q3. In the given figure, If AB || CD, ∠PTB = 55° and ∠DVS = 45°, then what is the sum of the measures of ∠CUQ and∠RTP?
SSC CGL Quantitative Aptitude : 11th February 2020 for Geometry and Co- ordinate Geometry_70.1
(a) 180°
(b) 135°
(c) 110°
(d) 100°

Q4. In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE ?
SSC CGL Quantitative Aptitude : 11th February 2020 for Geometry and Co- ordinate Geometry_80.1
(a) 20°
(b) 30°
(c) 40°
(d) 50°

Q5. A quadrilateral ABCD circumscribes a circle and AB = 6cm, CD= 5cm and AD= 7cm. The length of side BC is
(a) 4 cm
(b) 5 cm
(c) 3 cm
(d) 6 cm

SSC CGL 2019-20 | SSC CGL Maths Preparation | Geometry (Part 1)

Q6. If the chord of a circle is equal to the radius of the circle, then the angle subtended by the chord on center is
(a) 150°
(b) 60°
(c) 120°
(d) 30°

Q7. Diagonals of a || gm are 8 m and 6 m respectively. If one of side is 5 m, then the area of || gm is :
(a) 18 m²
(b) 30 m²
(c) 24 m²
(d) 48 m²

Q8. In the given figure AB || CD, given that ∠PEB = 80°, ∠QHD = 120° and ∠PQR =X°, find the value of x :
SSC CGL Quantitative Aptitude : 11th February 2020 for Geometry and Co- ordinate Geometry_90.1
(a) 40°
(b) 20°
(c) 100°
(d) 30°

Q9. Given a ∆PQR with vertices P (2, 3), Q (-3, 7) and R (-1, -3). The equation of median PM is .
(a) x- y + 10 = 0
(b) x- 4y – 10 = 0
(c) x- 4y+ 10 = 0
(d) None of these

Q10. Find the area of quadrilateral formed by straight lines x = 1, x = 3, y = 2 and x = y+ 3.
(a) 6 sq. units
(b) 12 sq. units
(c) 3 sq. units
(d) None of these

Solutions:

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