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**SSC Adda,**we provide you a test of 20 questions i.e. Test Of the Day(TOD) which play a vital role in your practice. In TOD, You’ll find all 4 subjects in a single quiz. We wish you Good luck for your**SSC CGL /MTS / CPO**exams. We are making all the possible efforts to make your Studies fun and Interactive.**Directions (1-2): In each of the questions, four alternatives are given for the Idiom/Phrase. Choose the alternative which best expresses the meaning of the Idiom/Phrase and click the button corresponding to it.**

**Q1. To beat about the bush**

To try to win favours

To talk well

To talk about relevant things

To talk about irrelevant things

Solution:

To beat about the bush-discuss a matter without coming to the point.

**Q2. Maiden speech**

Bachelor’s speech

First speech

Last speech

Extempore speech

Solution:

maiden speech: a person’s first speech

**Directions (3-5): Out of the four alternatives, choose the one which can be substituted for the given words/sentences and click the button corresponding to it.**

**Q3. A place where money is coined.**

Bank

Mint

Firm

Parliament

Solution:

Mint-A place where the coins of a country are manufactured by authority of the government.

**Q4. The process by means of which plants and animals breathe.**

Respiration

Germination

Absorption

Transpiration

Solution:

respiration-a process in living organisms involving the production of energy, typically with the intake of oxygen and the release of carbon dioxide from the oxidation of complex organic substances.

**Q5. One who sneers at the aims and beliefs of his fellow men.**

Critic

Connoisseur

Pedant

Cynic

Solution:

Cynic-a person who believes that people are motivated purely by self-interest rather than acting for honourable or unselfish reasons.

**Q6. In below alphabet series, one term is missing, which has been given as one of the four alternatives under it. This alternative is your answer. E, J, O, T, ?**

X

Y

Z

A

**Directions (7-8): In each of the following questions, there is some relationship between the two terms to the left of : : and the same relationship holds between the two terms to its right. Also, in each question, one term either to the right of : : or to the left of it is missing. The term is given as one of the alternatives given below each question. Find out this term.**

**Q7. CLOSE : DNRWJ : : OPEN : ?**

PRHR

PRJQ

RPJB

RZWR

Solution:

The first, second, third, fourth, fifth, ….. letters of the first group are moved one, two, three, four, five, ….. steps forward respectively to obtain the corresponding letters of the second group.

**Q8. 16 : 56 : : 32 : ?**

96

112

118

128

**Q9. In this question, four numbers are given. Out of these, three are alike in a certain way but the rest one is different. Choose the one which is different from the rest three.**

121

137

153

177

Solution:

121 is the only perfect square number in the group.

**Q10. In below numerical series, one term is missing, which has been given as one of the four alternatives under it. This alternative is your answer. 6, 12, 21, ? , 48**

33

38

40

45

Solution:

Pattern is +6, +9, +12, +15, ….

Missing term is = 33 b;

**Q11. The densest of all the atmosphere layers is**

Troposphere

Stratosphere

Mesosphere

Ionosphere

**Q12. The density of air is normally __________ at higher attitude.**

Increase

Decreases

Remains constant

Varies from place to place

**Q13. Of the following, the busiest ocean trade route is the**

Suez Canal

North Atlantic route

Panama Canal

Cape route

**Q14. The propagation of radio signals is greatly influenced by**

Troposphere

Ionosphere

Exosphere

Thermosphere

**Q15. The water cycle takes place in which sphere of the atmosphere?**

Tropopause

Stratosphere

Mesosphere

Troposphere

**Q16. A man cycles with a speed of 10 km/h and reaches his office at 1 pm. However, when he cycles with a speed of 15 km/h, he reaches his office at 11 am At what speed should he cycle so that he reaches his office at 12 noon?**

20 km

16 km

12 km

14 km

**Q17. Siddharth goes by a bike to pick up his girlfriend everyday from college and then drops her at her house. College timings are till 5 pm daily, but today the college was till 4 pm. His girlfriend, not finding Siddharth, at the college gate, starts walking towards her house. Siddharth, unaware of this fact, leaves his house as usual, meets his girlfriend on way, picks her up and drops her at her house. At night, Siddharth realize that he had saved 40 minutes that day. What is the ratio of the speed of Siddharth to that of his girlfriend? (Both of them live in the same building)**

2:1

1:2

2:3

3:2

Solution:

Let us see the following schematic representation:

The usual route of Siddharth is home-college-home. His route today is-home-meeting point-home. And, in this way, 40 minutes are saved. So, he takes 20 minutes to cover the distance between the meeting point and the college. It can be concluded that he usually reaches college at 5 pm, but today he reached at 4: 40 pm (20 minutes are saved) and his girlfriend took 40 minutes. (she starts at 4 pm) to cover the distance between her college to the meeting point.

The ratio of time of Siddharth and his girlfriend = 20: 40 = 1: 2

The ratio of the speed of Siddharth and his girlfriend = 2: 1

**Q18. Distance between two points AB = 110 km. Manoj starts running from A at a speed of 60 km/h and Ravi starts running from B at a speed of 40 km/h at the same time. They meet at a point X, somewhere on the line AB. What is ratio of AX to BX?**

3 : 2

1 : 2

4 : 3

6 : 1

Solution:

Since both Manoj and Ravi are running for the same time, T is constant. Hence, the ratio of the distance covered by them will be the same as the ratio of their speed.

So, AX/BX = Speed of Manoj /Speed of Ravi = 60/40 = 3: 2

**Q19. The speed of the boat in still water is 6 km/h and the speed of the river is 1.2 km/h. Boat takes a total of 10 h to go to a place and come back. What is the total distance covered in the whole process?**

52.3 km

48.4 km

55.6 km

57.6 km

Solution:

Upstream speed = 4.8 km/h

Downstream speed = 7.2 km/h

The ratio of downstream speed: upstream

Speed = 3: 2

Ratio of the downstream time: upstream time = 2: 3

The time taken in the downstream movement = 4 h and the time taken in the upstream movement = 6 h

So, the distance covered = 4×7.2+6×4.8=57.6 km

Hence, the total distance = 57.6 km

**Q20. In a race of 100 m, A gives a start of 10 m to B. Despite this, A wins the race by 20 m. What is the ratio of the speed of A and B?**

10 : 7

8 : 2

5 : 3

6 : 4

Solution:

Time taken by A to cover 70 m = Time taken by B to cover 100 m

Since the distance is constant, the ratio of speed of A and B = 10 : 7

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