SSC CGL 2015 : QUANT QUIZ

ANSWERS AND SOLUTION:
1(A)Explanation :
Radius of the circle (r) = 28 cm.
Length of the wire (circumference) = 2 pi r = 2 pi 28 = 176 cm
Let side of the square be “a” cm.
Perimeter of square(4a) = Circumference of the circle = 176 cm
or, 4a = 176 cm
or, a = 44 cm
 Thus, side of the square is 44 cm.

2(D)Explanation :
Simple Interest, SI = (3875 – 2500) = Rs.1375
Principal, P = Rs. 2500
Time, T = 4 years
R = ?
R = (100×SI)/PT= (100×1375)/2500×4 = 100×1375/10000=13.75%

3(A)Explanation:
15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days  4 odd days.
Jan.  Feb.   March    April    May  June  July  Aug.
(31 +  28  +  31   +   30   +  31  + 30  + 31  + 15) = 227 days
So  227 days = (32 weeks + 3 days)  3 odd days.
Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.
Given day is Sunday.

4(D)Explanation:
Let C = x.
Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.
So, x + x + 5000 + x + 9000 = 50000
=>  3x = 36000
=> x = 12000
A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.
 A’s share = Rs.(35000 x 21/50) = Rs. 14,700.

5(D)Explanation:
Here M1 = 40, T1 = 8 hours, W1 = 60 and M2 = 32, T2 = 12, W2 = ?
M1 x T1 x W2 = M2 x T2 x W1
So 40 x 8 x W2 = 32 x 12 x 60
or, W2 =  23040/320 = 72

6(B)Explanation:
Let the required number of bottles be x.
More machines, More bottles (Direct Proportion)
More minutes, More bottles (Direct Proportion)
Machines           6 : 10
                         ::  270 : x
Time (in minutes) 1 :  4
So  6 x 1 x x = 10 x 4 x 270
 x = (10 x 4 x 270)/(6)
 x = 1800.

7(A)Explanation:
Let cost price of goods be Rs 100.
Gain = 20%
Therefore, selling price = Rs 120
Discount = 25%
Marked Price = (100/(100 – 25) x 120)
= Rs. 160
i .e. 60% more

8(C)Explanation:
Let the numbers be 2x and 3x.
Then, their L.C.M. = 6x.
So, 6x = 48 or x = 8.
So,  The numbers are 16 and 24.
Hence, required sum = (16 + 24) = 40.

9(A)Explanation :
Length of the train, l = 150m
Speed of the man , Vm= 2 km/hr
Relative speed, Vr = total distance/time = (150/3) m/s = (150/3) × (18/5) = 180 km/hr
Relative Speed = Speed of train, Vt – Speed of man (As both are moving in the same direction)
=> 180 = Vt – 2
=> Vt = 180 + 2 = 182 km/hr

10(D)Explanation:
A : B = 100 : 90.
A : C = 100 : 87.
B/C = B/A x A/C = 90/100 x 100/87 = 30/29 .
When B runs 30 m, C runs 29 m.
When B runs 180 m, C runs (29/30 x 180) m = 174 m.
 B beats C by (180 – 174) m = 6 m.