**1. A wire is in the form of a circle . The radius of the circle is 28 cm. The wire is then moulded to form a square . find the side of the square formed?**

**2. A sum of Rs. 2500 amounts to Rs. 3875 in 4 years at the rate of simple interest. What is the rate of interest?**

**3. What will be the day of the week 15th August, 2010?**

**4. A, B, C subscribe Rs. 50,000 for a business. A subscribes Rs. 4000 more than B and B Rs. 5000 more than C. Out of a total profit of Rs. 35,000, A receives:**

**5. 40 men can make 60 toys in 8 hours. if 8 men leave the work then how many toys can be made in 12 hours?**

**6. Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?**

**7. How much percent more than the cost price should a shopkeeper mark his goods so that after allowing a discount of 25% on the marked price , he gain 20% ?**

**8. The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is:**

**9. A train has a length of 150 meters . it is passing a man who is moving at 2 km/hr in the same direction of the train, in 3 seconds. Find out the speed of the train.**

**10. In a 100 m race, A beats B by 10 m and C by 13 m. In a race of 180 m, B will beat C by:**

**ANSWERS AND SOLUTION:**

**1(A)Explanation :**

Radius of the circle (r) = 28 cm.

Length of the wire (circumference) = 2 pi r = 2 pi 28 = 176 cm

Let side of the square be “a” cm.

Perimeter of square(4a) = Circumference of the circle = 176 cm

or, 4a = 176 cm

or, a = 44 cm

Thus, side of the square is 44 cm.

**2(D)Explanation :**

Simple Interest, SI = (3875 – 2500) = Rs.1375

Principal, P = Rs. 2500

Time, T = 4 years

R = ?

R = (100×SI)/PT= (100×1375)/2500×4 = 100×1375/10000=13.75%

**3(A)Explanation:**

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.

Jan. Feb. March April May June July Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days

So 227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday.

**4(D)Explanation:**

Let C = x.

Then, B = x + 5000 and A = x + 5000 + 4000 = x + 9000.

So, x + x + 5000 + x + 9000 = 50000

=> 3x = 36000

=> x = 12000

A : B : C = 21000 : 17000 : 12000 = 21 : 17 : 12.

A’s share = Rs.(35000 x 21/50) = Rs. 14,700.

**5(D)Explanation:**

Here M1 = 40, T1 = 8 hours, W1 = 60 and M2 = 32, T2 = 12, W2 = ?

M1 x T1 x W2 = M2 x T2 x W1

So 40 x 8 x W2 = 32 x 12 x 60

or, W2 = 23040/320 = 72

**6(B)Explanation:**

Let the required number of bottles be x.

More machines, More bottles (Direct Proportion)

More minutes, More bottles (Direct Proportion)

Machines 6 : 10

:: 270 : x

Time (in minutes) 1 : 4

So 6 x 1 x x = 10 x 4 x 270

x = (10 x 4 x 270)/(6)

x = 1800.

**7(A)Explanation:**

Let cost price of goods be Rs 100.

Gain = 20%

Therefore, selling price = Rs 120

Discount = 25%

Marked Price = (100/(100 – 25) x 120)

= Rs. 160

i .e. 60% more

**8(C)Explanation:**

Let the numbers be 2x and 3x.

Then, their L.C.M. = 6x.

So, 6x = 48 or x = 8.

So, The numbers are 16 and 24.

Hence, required sum = (16 + 24) = 40.

**9(A)Explanation :**

Length of the train, l = 150m

Speed of the man , Vm= 2 km/hr

Relative speed, Vr = total distance/time = (150/3) m/s = (150/3) × (18/5) = 180 km/hr

Relative Speed = Speed of train, Vt – Speed of man (As both are moving in the same direction)

=> 180 = Vt – 2

=> Vt = 180 + 2 = 182 km/hr

**10(D)Explanation:**

A : B = 100 : 90.

A : C = 100 : 87.

B/C = B/A x A/C = 90/100 x 100/87 = 30/29 .

When B runs 30 m, C runs 29 m.

When B runs 180 m, C runs (29/30 x 180) m = 174 m.

B beats C by (180 – 174) m = 6 m.

A,d,-,d,d,b,a,-,a,-

1 A

2 D

3 A

4 D

5 D

6 B

7 D

8 C

9 A

10 A

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Important "Idoms & Phrases"

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