RRB JE Stage II exam is scheduled to be conducted from 28th August to 1st September 2019. The overall merit for the selection will be made on the basis of the marks scored in stage II, so candidates need to prepare thoroughly for the second stage. To help the aspirants, Adda247 has come up with a study plan in which we will provide you daily quizzes of all technical subjects. The below quiz will be helpful for the candidates who opted Electronics as the exam group in RRB JE stage II.
Q1. In a force-voltage analogy, velocity is analogous to
Sol. In force-voltage analogy, velocity is analogous to the current in force-voltage that is also called series circuit.
Q2. Intrinsic semiconductor at d 0°K will have ……….. available for conduction.
(c) both electron and holes
Sol. An intrinsic semiconductor is a pure semiconductor, i.e., a sample without any impurity. At absolute zero it is essentially an insulator, though with a much smaller band gap. However, at any finite temperature there are some charge carriers are thermally excited, contributing to conductivity.
Q3. Where n is the number of the shell, the maximum number of electrons in the shell can be
Sol. Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on. The general formula is that the nth shell can in principle hold up to 2(n2) electrons.
Q4. In Binary code shifting a register to left by one bit position is equivalent to
(a) subtraction of 2
(b) addition of 2
(c) division of 2
(d) multiplication by 2
Sol. Shifting a binary number by one bit is equivalent to multiplying (when shifting to the left) or dividing (when shifting to the right) the number by 2.
Q5. A counter in which the output of one flip-flop acts as clock for other is termed
(b) ripple counter
(c) ring counter
(d) synchronous counter
Sol. A ripple counter is an asynchronous counter where only the first flip-flop is clocked by an external clock. All subsequent flip-flops are clocked by the output of the preceding flip-flop.
Q6. Find IC, given VCE=0.77v, VCC=10v, VBE=0.37v and RC=2.4kΩ in Dual Input Balanced Output differential amplifier
Sol. Substitute the values in collector to emitter voltage equation,
VCE= VCC+ VBE-RC IC
⇒IC = (VCC-VCE+VBE)/RC = (10v-0.77v+0.37v)/2.4kΩ = 4mA
Q7. The quantization noise of a PCM system depends on
(a) Number of quantization levels
(c) Both step-size and number of quantization levels
(d) Sampling rate
Q8. A terminal where three or more branches meet is known as
Sol. A node is any point on a circuit where the terminals of two or more circuit elements meet.
Q9. The Laplace transform of a unit parabolic function is
Sol. Laplace transform of unit parabolic function = 2/s3.
Q10. The peak value of a sine wave is 200 V. Its average value is
(a) 127.4 V
(b) 141.4 V
(c) 282.8 V
(d) 300 V
Sol. Vavg= 0.637 x Vp
Vavg = 0.637×200 = 127.4 V
You may also like to read:
- Check RRB JE STAGE 1 result
- RRB JE Cut Off 2019: Check Region-wise Cut Off
- Check RRB JE Stage II Exam Pattern & Syllabus
- Click here for RRB JE Salary & Job Profile Details
- Click Here to view Latest Govt. Jobs 2019