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Home RRB JE Stage-II RRB JE Stage II : Electronics Engineering Quiz | 21st August 2019

RRB JE Stage II : Electronics Engineering Quiz | 21st August 2019

Dear aspirants,

RRB JE Stage II exam is scheduled to be conducted from 28th August to 1st September2019. The overall merit for the selection will be made on the basis of the marks scored in stage II, so candidates need to prepare thoroughly for the second stage. To help the aspirants, Adda247 has come up with a study plan in which we will provide you daily quizzes of all technical subjects. The below quiz will be helpful for the candidates who opted Electronics as the exam group in RRB JE stage II. 

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Q1. Mass, in force-voltage analogy, is analogous to
(a) charge
(b) current
(c) inductance
(d) resistance

S1. Ans.(c)
Sol. Mass, in force-voltage analogy, is analogous to inductance.

Q2. With feedback…………..increases
(a) system stability
(b) sensitivity
(c) gain
(d) effects of disturbing signals

S2. Ans.(a)
Sol. With feedback system stability increases.

Q3. For a germanium P-N junction, the barrier potential is nearly
(a) 0.15 V
(b) 0.3 V
(c) 0.45 V
(d) 0.6 V

S3. Ans.(b)
Sol. The potential barrier in the P-N junction is the barrier which does not allow charge flow across the junction normally. The barrier potential of germanium is approximately 0.3 V, and of silicon is 0.7 V.

Q4. In order to obtain a P-type germanium, the germanium should be doped with a …….. impurity.
(a) trivalent
(b) tetravalent
(c) pentavalent
(d) any of the above

S4. Ans.(a)
Sol. In order to obtain a P-type germanium, the germanium should be doped with a trivalent impurity.

Q5. The varactor is widely used in
(a) FM receivers
(b) TV receivers
(c) communication equipment
(d) all of the above.

S5. Ans.(d)
Sol. Varactor diodes are widely used within RF circuits. They provide a method of varying the capacitance within a circuit by the application of a control voltage. This gives them an almost unique capability and as a result varactor diode are widely used within the RF industry.

Q6. The number of nibbles which make up one byte is …..
(a) 2
(b) 4
(c) 8
(d) 16

S6. Ans.(a)
Sol. The number of nibbles which make up one byte is 2 because we know 4 bit is equal to 1 nibble and
1 byte = 8 bit.

Q7. A semiconductor Read-only-memory basically is
(a) a set of flip-flop memory elements x`x`
(b) a combinational logic circuit
(c) a sequential circuit with flip-flops and gates
(d) none of the above

S7. Ans.(b)
Sol. A semiconductor Read-only-memory basically is a combinational logic circuit.

S8. Ans.(d)
Sol. The power dissipated in 30 Ω resistor will be maximum when maximum current will pass through 30 Ω resistor.

Q10. In a PCM system each quantization level is encoded into 8 bits. The signal to quantization noise ratio is equal to
(a) 24 dB
(b) 48 dB
(c) 64 dB
(d) 256 dB

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