RRB JE Reasoning Questions 2019: 18th February

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As you all know, RRB JE Exam will be held in the month of april/may 2019. We are providing daily learning quizzes, we aim to provide the best study materials to our students. Attempt this quiz and check your preparation.  

 

Directions (1-4): For each of the following questions there is some relationship between the two terms to the left of :: and there is same relationship between the two terms to its right. In each of these questions the fourth term is missing. Find out this term.
निम्नलिखित में से प्रत्येक प्रश्न में, :: के बायें ओर के दो पदों के बीच कुछ सम्बन्ध है और :: के दायें ओर के दो पदों के बीच भी समान सम्बन्ध है। निम्नलिखित में से प्रत्येक प्रश्न में चौथा पद लुप्त है। यह पद ज्ञात कीजिये।
Q1. CLQH : EOSK : : DNPH : ?
(a) FQKR
(b) FKQR
(c) FKRQ
(d) FQRK

S1. Ans. (d);
Sol. Each term follows (+2,+3+2,+3) pattern.

Q2. 6 : 223 : : 5 : ?
(a) 100
(b) 152
(c) 125
(d) 131

Q3. 64 : 64 : : ? : 512
(a) 256
(b) 144
(c) 64
(d) 81

S3. Ans. (a);
Sol. First term = (8)² = 64
Second term = (4)3 = 64
Similarly,
Third term = (16)2 = 256
Fourth term = (8)3 = 512

Q4. USA : Dollar : : North Korea : ?
यू.एस.ए. : डॉलर : : उत्तर कोरिया : ?
(a) Yuan/ युआन
(b) Euro/ यूरो
(c) Won/ वॉन
(d) Peso/ पेसो

S4. Ans. (c);
Sol. Dollar is the currency of USA. Similarly, Won is the currency of North Korea.

Q5. Find the odd word from the given alternatives.
दिए गए विकल्पों में से विषम शब्द को चुनिये।
(a) Jantar Mantar/ जंतर-मंतर
(b) Red Fort/ लाल किला
(c) Taj Mahal/ ताजमहल
(d) Qutub Minar/ क़ुतुब मीनार

S5. Ans. (c);
Sol. Except Taj Mahal, all other monuments are situated in Delhi

Q6. Select the odd letters from the given alternatives.
दिए गए विकल्पों में से विषम अक्षर को चुनिये।
(a) BFJ
(b) JNR
(c) NRV
(d) FJM

S6. Ans. (d);
Sol. Except FJM, All other letters follow +4 pattern.

Q7. Select the odd number from the given alternatives.
दिए गए विकल्पों में से विषम संख्या को चुनिये।
(a) 2147
(b) 3155
(c) 4639
(d) 2084


S7. Ans. (c);
Sol. 2 × 7 = 14
3 × 5 = 15
4 × 9 = 36 ≠ 63
2 × 4 = 8

Q8. Rajan walks 10m north. Then he turns right and walks 15m. Then he turns right and walk 17m. Then he turns left and walks 7m. Finally he turns left and walks 7m. In which direction and how many metres is he from the starting point.
राजन उत्तर दिशा की ओर 10 मीटर चलता है। फिर वह दायीं ओर मुड़ता है और 15 मीटर चलता है। वह फिर से दायीं ओर मुड़ता है और 17 मीटर चलता है। फिर वह बायीं ओर मुड़ता है और 7 मीटर चलता है। अंततः वह बायीं ओर मुड़ता है और 7 मीटर चलता है। अब वह शुरूआती बिंदु से कितनी दूर और कौन सी दिशा में है?
(a) 22m east / मीटर पूर्व
(b) 8m east / मीटर पूर्व
(c) 8m west / मीटर पश्चिम
(d) 22m west / मीटर पश्चिम

Q9. In this question, a word is represented by only one set of numbers as given in any one of the alternatives. The sets of numbers given in the alternatives are represented by two classes of alphabets as in the two given matrices. The columns and rows of Matrix I are numbered from 0 to 4 and those of Matrix II from 5 to 9. A letter from these matrices can be represented first by its row and then the column number.
You have to identify the correct set for the word “SODA”
एक शब्द केवल एक संख्या-समूह द्वारा दर्शाया गया है, जैसा कि विकल्पों में से किसी एक में दिया गया है विकल्पों में दिए गए संख्या-समूह अक्षरों के दो वर्गों द्वारा दर्शाए गए हैं, जैसा कि नीचे गए दो आव्यूहों में है। आव्यूह I के स्तम्भ और पंक्ति की संख्या 0 से 4 तक दी गई है और आव्यूह II की 5 से 9 तक, इन आव्यूहों से एक अक्षर को पहले उसकी पंक्ति और बाद में स्तम्भ संख्या द्वारा दर्शाया जा सकता है। आपको दिए शब्द “SODA” के लिए सही समूह को पहचानना है।

(a) 02, 24, 12, 98
(b) 34, 87, 87, 98
(c) 43, 30, 41, 44
(d) 34, 24, 14, 44

S9. Ans. (d);
Sol. SODA = 34, 24, 14, 44

Q10. A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
एक श्रृंखला दी गई है, जिसमें से एक पद लुप्त है। दिए गए विकल्पों में से वह सही विकल्प चुनिए, जो इस श्रृंखला को पूरा करेगा।
101, 170, 257, ?
(a) 399
(b) 400
(c) 362
(d) 402

S10. Ans. (c);
Sol. 10² + 1 = 101 , 10+3 = 13
13² + 1 = 170, 13+3 =16
16² + 1 = 257, 16+3= 19
19² + 1 = 362

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