Last updated at Feb. 1, 2020 by Teachoo

Transcript

Ex 11.2, 5 Find the equation of the line in vector and in cartesian form that passes through the point with position vector 2๐ ฬ โ ๐ ฬ + 4๐ ฬ and is in the direction ๐ ฬ + 2 ๐ ฬ โ ๐ ฬ . Equation of a line passing though a point with position vector ๐ โ and parallel to vector ๐ โ is ๐ โ = ๐ โ + ๐ ๐ โ Here, ๐ โ = 2๐ ฬ โ ๐ ฬ + 4๐ ฬ & ๐ โ = ๐ ฬ + 2๐ ฬ โ ๐ ฬ So, ๐ โ = (2๐ ฬ โ ๐ ฬ + 4๐ ฬ) + ๐ (๐ ฬ + 2๐ ฬ โ ๐ ฬ) โด Equation of line in vector form is (2๐ ฬ โ ๐ ฬ + 4๐ ฬ) + ๐ (๐ ฬ + 2๐ ฬ โ ๐ ฬ) Equation of a line passing though (x1, y1, z1) and parallel to a line having direction ratios a, b, c is (๐ฅ โ ๐ฅ1)/๐ = (๐ฆ โ ๐ฆ1)/๐ = (๐ง โ ๐ง1)/๐ Since the line passes through a point with position vector 2๐ ฬ โ ๐ ฬ + 4๐ ฬ, โด ๐ฅ1 = 2, y1 = โ1, z1 = 4 Also, line is in the direction of ๐ ฬ + 2๐ ฬ โ ๐ ฬ, Direction ratios : ๐ = 1, b = 2, c = โ1 Equation of line in Cartesian form is (๐ฅ โ 2)/1 = (๐ฆ โ ( โ1))/2 = (๐ง โ 4)/( โ 1) (๐ โ ๐)/๐ = (๐ + ๐)/๐ = (๐ โ ๐)/( โ ๐)

Ex 11.2

Ex 11.2, 1

Ex 11.2, 2

Ex 11.2, 3 Important

Ex 11.2, 4

Ex 11.2, 5 Important You are here

Ex 11.2, 6

Ex 11.2, 7 Important

Ex 11.2, 8

Ex 11.2, 9 Important

Ex 11.2, 10 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 10 (ii)

Ex 11.2, 11 (i) Important Deleted for CBSE Board 2022 Exams

Ex 11.2, 11 (ii)

Ex 11.2, 12 Important

Ex 11.2, 13

Ex 11.2, 14 Important

Ex 11.2, 15 Important

Ex 11.2, 16

Ex 11.2, 17 Important

Chapter 11 Class 12 Three Dimensional Geometry (Term 2)

Serial order wise

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.