Reasoning Quiz For SSC Exams : 21st October

Dear aspirants,

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Direction (1-10): A series is given with one term missing. Choose the correct alternative from the given ones that will complete the series.
एक श्रंखला दी गई है जिसमें एक टर्म अज्ञात हैं आपको दिए गए विकल्पों में से उस विकल्प का चयन करना है जो इस श्रंखला को पूरा करेगा?

Q1. 16,33, 65, 131, 261, (….)
A. 523
B. 521
C. 613
D. 721

S1. Ans. (A)
Sol. Each number is twice the preceding one
with 1 added or subtracted alternatively.
So, the next number is (2 x 261 + 1) = 523.

Q2. 10,5, 13, 10, 16, 20, 19, (….)
A. 22
B. 40
C. 38
D. 23

S2. Ans. (B)
Sol. There are two series (10, 13, 16, 19) and (5, 10, 20, 40), one increasing by 3 and the other multiplied by 2.

Q3. 1,4, 9, 16, 25, 36, 49, (….)
A. 54
B. 56
C. 64
D. 81

S3. Ans. (C)
Sol. Numbers are 1², 2², 3², 4², 5², 6², 7².
So, the next number is 8² = 64.

Q4. 2,4, 12, 48, 240, (….)
A. 960
B. 1440
C. 1080
D. 1920

S4. Ans. (B)
Sol. Go on multiplying the given numbers by 2, 3, 4, 5, 6.
So, the correct next number is 1440.

Q5. 8,7, 11, 12, 14, 17, 17, 22, (….)
A. 27
B. 20
C. 22
D. 24

S5. Ans. (B)
Sol. There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.

Q6. 11,13, 17, 19, 23, 29, 31, 37, 41, (….)
A. 43
B. 47
C. 53
D. 51

S6. Ans. (A)
Sol. Numbers are all primes. The next prime is 43

Q7. 8,24, 12, 36, 18, 54, (….)
A. 27
B. 108
C. 68
D. 72

S7. Ans. (A)
Sol. Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.

Q8. 2,6, 12, 20, 30, 42, 56, (….)
A. 61
B. 64
C. 72
D. 70

S8. Ans. (C)
Sol. The pattern is 1 x 2, 2 x 3, 3 x 4, 4 x 5, 5 x 6, 6 x 7, 7 x 8. So, the next number is 8 x 9 = 72.

Q9. 4,-8, 16, -32, 64, (….)
A. 128
B. -128
C. 192
D. -192

S9. Ans. (B)
Sol. Each number is the proceeding number multiplied by -2. So, the required number is -128.

Q10. 7,26, 63, 124, 215, 342, (….)
A. 481
B. 511
C. 391
D. 421

S10. Ans (b)
Sol. Numbers are (2³ – 1), (3³- 1), (4³ – 1), (5³ – 1), (6³ – 1), (7³ – 1) etc.
So, the next number is (8³ – 1) = (512 – 1) = 511.

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