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Dear aspirants,
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Direction(1-10) : Following series are given below with one term missing. Choose the correct alternative from the given ones that will complete the series.
एक श्रंखला दी गई है जिसमें एक टर्म अज्ञात हैं आपको दिए गए विकल्पों में से उस विकल्प का चयन करना है जो इस श्रंखला को पूरा करेगा?
Q1. 2, 5, 9, 19, 37 ?
(a) 73
(b) 75
(c) 76
(d) 78
S1. Ans. (b)
Sol. Clearly, we have: 2 x 2 + 1= 5, 5 x 2 -1 = 9, 9 x 2 + 1 = 19, 19 x 2 -1 = 37,
So, missing term = 37 x 2 + 1 =75.
Q2. 22, 24, 28, ?, 52, 84
(a) 36
(b) 38
(c) 42
(d) 46
S2. Ans. (a)
Sol. The pattern is +2, +4, +8, +16
So, missing term = 28 + 8 = 36.
Q3. 1, 4, 27, 16, ?, 36, 343
(a) 25
(b) 87
(c) 120
(d) 125
S3. Ans. (d)
Sol. Clearly, the given the series consists of cubes of odd numbers and squares of even numbers, I. e, 13, 23, 33, 43, ….
So, missing term = 53 = 125.
Q4. 1/2, 3/4, 5/8, 7/16, ?
(a) 9/32
(b) 10/17
(c) 11/34
(d) 12/35
S4. Ans. (a)
Sol. Clearly, the numerators of the fractions in the given sequence form the series 1, 3, 5, 7, in which each term is obtained by adding 2 to the previous term.The denominators of the fractions form the series 2, 4, 8, 16, i.e. 21, 22, 23, 24.So, the numerator of the fractions will be (7 +2) i.e. 9 and the denominator will be 25 i.e. 32.
Thus, the next term is 9/32.
Q5. 1, 9, 25, 49, ?, 121
(a) 64
(b) 81
(c) 91
(d) 100
S5. Ans. (b)
Sol. The given series consists of squares of consecutive odd numbers i.e. 12, 32, 52,72,…… So, missing term = 92 =81
Q6. B, D, F, I, L, P, ?
(a) R
(b) S
(c) T
(d) U
S6. Ans. (c)
Sol. B(+2)→D (+2)→ (+3)→ (+3)→ (+4)→P (+4)→T
Q7. U,B,I,P,W ,?
(a) D
(b) F
(c) Q
(d) U
S7. Ans. (a)
Sol. U (+7)→B (+7)→I (+7)→P (+7)→ (+7)→D
Q8. Z, ?, T, ?, N, ?, H, ?, B
(a) W,Q,K,E
(b) W,R,K,E
(c) X,Q,K,E
(d) X,R,K,E
S8. Ans. (a)
Sol. Z (-6)→T (-6)→N (-6)→ (-6)→B
Z (-3)→ (-3)→T (-3)→Q (-3)→N (-3)→K (-3)→H (-3)→ (-3)→B
Q9. a , d , c , f , ?, h , g , ? , i
(a) e, j
(b) e, k
(c) f, j
(d) j, e
S9. Ans. (a)
Sol. a (+3)→d (-1)→c (+3)→f (-1)→e (+3)→ (-1)→g (+3)→j (-1)→i.
Q10. A, I, P, V, A, E, ?
(a) E
(b) F
(c) G
(d) H
S10. Ans. (d)
Sol. A (+8)→I (+7)→P (+6)→V (+5)→A (+4)→E (+3)→H
