**For the first time SSC 2016 examination will be held in Computer Based pattern and managing time will be one of the important factor while solving the questions. So in order to make students familiar with such a situations we are providing questions in a time based manner , which will help students to manage the time properly.**

**irections (Q.1-7): Find the missing character in each of the following:**

**1.**

** **

10

11

12

13

Solution:

The numbers in the right half form the series : 2, 3, 4, 5.

The numbers in the left half form the series : 5, 7, 9, 11.

The numbers in the left half form the series : 5, 7, 9, 11.

2.

** **

18

33

135

145

Solution:

We have: 15 × 2 = 30, 2 × 7 = 14, 7 × 9 = 63.

So,

missing number = 9 × 15 = 135.

So,

missing number = 9 × 15 = 135.

**3.**

** **

12

21

24

35

Solution:

We have: (27+54 )/9=9; (42+84 )/14=9.

Let the missing number be x. Then, (x+42)/7=9⇔x=21.

Let the missing number be x. Then, (x+42)/7=9⇔x=21.

**4.**

125

215

251

512

Solution:

The numbers obtained by squaring the numbers at the bottom are combined together

physically to get the number in the upper part.

physically to get the number in the upper part.

**5.**

35

37

45

46

Solution:

We have: 11 + 22 + 33 + 44 = 110; 16 + 24 + 32 + 40 = 112.

So, missing number = 114 – (23 + 34 + 12) = 45.

So, missing number = 114 – (23 + 34 + 12) = 45.

6.

35

48

72

120

Solution:

We have : (15 – 5) × (2 + 6) = 80, (9 – 4) × (7 + 6) = 65

So, missing number = (13 – 11) × (16 + 8) = 48.

So, missing number = (13 – 11) × (16 + 8) = 48.

**7.**

127

142

158

198

Solution:

We have : (101 + 15) – (35 + 43) = 38.

So, missing number = (48 + 184) – (56 + 34) = (232 – 90) = 142.

So, missing number = (48 + 184) – (56 + 34) = (232 – 90) = 142.

**Directions (Q. 8-10): In each of the following questions, a matrix of certain characters is given. These characters follow a certain trend, row-wise or column-wise. Find out this trend and choose the missing character from the given alternatives. **

** 8.**

** **

1

2

3

4

Solution:

In the first column, (6 + 7) × 5 = 65

In the second column, (3 + 2) × 4 = 20.

In the third column , (1+4) x 9= 45

In the second column, (3 + 2) × 4 = 20.

In the third column , (1+4) x 9= 45

9.

1 3 7

** 5 12 14 **

** 25 ? 28 **

** 125 192 56**

64

56

48

40

Solution:

The sequence in first column is × 5.

Thus, 1 × 5 = 5, 5 × 5 = 25, 25 × 5 = 125.

The sequence in third column is × 2.

Thus, 7 × 2 = 14, 14 × 2 = 28, 28 × 2 = 56.

The sequence in second column is × 4.

∴ Missing number = 12 × 4 = 48.

Thus, 1 × 5 = 5, 5 × 5 = 25, 25 × 5 = 125.

The sequence in third column is × 2.

Thus, 7 × 2 = 14, 14 × 2 = 28, 28 × 2 = 56.

The sequence in second column is × 4.

∴ Missing number = 12 × 4 = 48.

**10.
188 300 236 **

**893 ? 915**

88

96

238

500

Solution:

In the first row, (263 – 188) × 4 = 300

∴ In the second row, missing number = (915 – 893) × 4 = 22 × 4 = 88.

∴ In the second row, missing number = (915 – 893) × 4 = 22 × 4 = 88.