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Home Reasoning Reasoning Quiz For SSC CGL : 7th December

Reasoning Quiz [Advanced level] For SSC CGL : 7th December

Q1.In the following question, select the odd letter/letters from the given alternatives.
(a) ADG
(b) HKN
(c) RUY
(d) GJM

Q2.Arrange the given words in the sequence in which they occur in the dictionary.
1. Sonorous
2. Sometimes
3. Somber
4. Solution
5. Solve
(a) 42513
(b) 45321
(c) 12543
(d) 32415

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Q3.In the following question, select the missing number from the given series.
2187, 729, 243, 81, 27, ?
(a) 10
(b) 9
(c) 13
(d) 11

Q4.A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
BKP, EMQ, IPS, NTV, ?
(a) TYZ
(b) SXY
(c) SYZ
(d) TXY

Q5.In a row of trucks, Ashok is at 17th position from the left end. Bharat is 19 places to the right from Ashok and is at the exact centre of the row. How many trucks are there to the right of Ashok truck?
(a) 53
(b) 54
(c) 52
(d) 19

Q6.From the given alternatives, select the word which CANNOT be formed using the letters of the given word.
Accounting
(a) Count
(b) Actually
(c) Acting
(d) Ant

Q7.In a certain code language, “MAYOR” is written as “NBZPS”. How is “PLAYER” written in that code language?
(a) QBFTRZ
(b) ZRBMQF
(c) QMBZFS
(d) RBMQFS

Q8.In a certain code language, ‘x’ represents ‘+’, ‘÷’ represents ‘x’, ‘-‘ represents ‘÷’ and ‘+’ represents ‘-‘. Find out the answer to the following question.
5 + 10 x 21 ÷ 5 – 15 = ?
(a) 49
(b) 2
(c) 30
(d) 24

Q9.The following equation is incorrect. Which two signs should be interchanged to correct the equation?
10 x 4 + 5 – 30 ÷ 6 = 31
(a) x and –
(b) ÷ and –
(c) + and ÷
(d) – and +

Q10.If 3*1 = 20, 6*1 = 50 and 2*6 = -40, then find the value of 5*8 = ?
(a) 100
(b) 30
(c) -50
(d) -30

S1. Ans.(c)
Sol. +3 series except RUY

S2. Ans.(b)
Sol. 4. Solution
5. Solve
3. Somber
2. Sometimes
1. Sonorous

S3. Ans.(b)
Sol.

S4. Ans.(a)
Sol.

S5. Ans.(b)
Sol.

S6. Ans.(b)
Sol. Actually

S7. Ans.(c)
Sol. QMBZFS (+ 1 series)

S8. Ans.(b)
Sol. 5 + 10 × 21 ÷ 5 – 15
⇒ 5 – 10 + 21 × 5 ÷ 15
⇒ 5 – 10 + 21 × 5/15
⇒ 5 – 10 + 7
⇒ 12 – 10 = 2

S9. Ans.(a)
Sol. 10×4+5–30÷6=31
⇒ 10–4+5×30÷6=31
⇒ 10–4+25=31
⇒ 35–4=31
⇒ 31 = 31

S10. Ans.(d)
Sol. (3–1)×10=20
(6–1)×10=50
(2–6)×10=–40
(5–8)×10=–30

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