**Direction(1-5): Select the related letters/word/number from the given alternative.**

**1. F × H : 21 × 19 : : M × O : ?**

(a) 13 × 15

(b) 14 × 12

(c) 20 × 19

(d) 21 × 23

(a) FHJL

(b) FHIK

(c) FHKM

(d) FGKL

**3. 4 : 8 : : 1 : ?**

(a) 9

(b) 3

(c) 1

(d) 0

**4. 10 : 14 : : 7 : ?**

(a) 9

(b) 13

(c) 15

(d) 17

**5. LIME : 20 : : LEMON : ?**

(a) 60

(b) 30

(c) 40

(d) 50

**Direction (6 – 7): Which one set of letters when sequentially placed at the gaps will complete the given letter series?**

**6. ab_accab_acc_bba_cabba_c**

(a) bbacc

(b) acbcc

(c) bcabb

(d) bcbba

**7. aa_abba_babbaa_ab_**

(a) babb

(b) baba

(c) aaba

(d) abaa

**8. If FUTURE is coded as UFTUER then how will NATURE be coded ?**

(a) ANUTER

(b) ANTURE

(c) ANTUER

(d) ANUTRE

**9. If TEA is coded as 100, then how will you code FAT?**

(a) 120

(b) 150

(c) 140

(d) 130

**10. If A represents ‘×’, B represents ‘÷’, C represents ‘+’ and D represents ‘-‘’, then find the value of 2 A 8 D 5 C 9 B 3?**

(a) 11

(b) 13

(c) 15

(d) 14

**11. Which of the following words cannot be formed using the letters of the word ‘APPROPRIATE’?**

(a) PIRATE

(b) APPROVE

(c) PROPER

(d) RAPPORT

**12. If**

**63 @ 81 = 2;**

**54 @ 51 = 3,**

**then 69 @ 21 = ?**

(a) 4

(b) 5

(c) 8

(d) 9

**For Q13 – 14:**

**In a class of 60 students, the number of boys is double of the number of girls. In a class test, Kapil’s rank is 10th from the top and there are 3 girls ahead of him in rank.**

**13. How many boys are below him in rank?**

(a) 31

(b) 32

(c) 33

(d) 34

**14. How many girls are below him in rank?**

(a) 14

(b) 15

(c) 16

(d) 17

**15. From the given alternatives select the word which can be formed using the letters given in the word.**

**LACKADAISICAL**

(a) LACHES

(b) DELICT

(c) KIDDLE

(d) SCALD

**Directions (16-17) Find out the missing number from the given options.**

**16.**

(a) 136

(b) 148

(c) 150

(d) 164

**17.**

(a) 40

(b) 54

(c) 68

(d) 92

**18. According to the different positions of dice as shown below, what will be on opposite face of 3?**

(a) 6

(b) 4

(c) 3

(d) 2

**19. If a mirror is placed on the line MN, then which of the answer figures is the correct image of the given question figure?**

**Question Figure:**

**Answer Figures:**

**20. A word is represented by only set of numbers as given in any of the alternatives. The sets of numbers given in the alternatives are represented by two classes of alphabets as in the 2 matrices given below. The columns and rows of matrix I are numbered from 0 to 4 and that of matrix II from 5 to 9. A letter from these matrices can be column number. E.g. ‘F’ and be represented by 14, 21, etc. ‘T’ can be represented by 59, 78 etc. Similarly identify the set for the word**

__“POSE”__.

**MATRIX (I)**

**MATRIX (II)**

(a) 87, 55, 89, 43

(b) 68, 98, 58, 21

(c) 75, 86, 67, 14

(d) 56, 67, 77, 01

__Answers:__
1:

(b)

(b)

21

and 19 represents the number of letters that come after F and H in alphabetical

sequence.

and 19 represents the number of letters that come after F and H in alphabetical

sequence.

2:

(a)

(a)

In

the group MNOP, the letters are shifted +1, +2, +3, +4 places in alphabetical

sequence to get NPRT. Similarly, EFGH can be converted to FHJL

the group MNOP, the letters are shifted +1, +2, +3, +4 places in alphabetical

sequence to get NPRT. Similarly, EFGH can be converted to FHJL

3:

(c)

(c)

4

and 8 are 2

are the next numbers in the group.

and 8 are 2

^{2}and 2^{3}respectively. So, 1^{2}and 1^{3}are the next numbers in the group.

4:

(a)

(a)

10/2

+ 2 = 7

+ 2 = 7

Therefore,

14/2 + 2 = 9

14/2 + 2 = 9

5:

(b)

(b)

The

sum of alphabetical positions of L, I, M and E is 12+9+13+5=39. So,

39+1=40/2=20.

sum of alphabetical positions of L, I, M and E is 12+9+13+5=39. So,

39+1=40/2=20.

The

sum of alphabetical positions of L, E, M, O and N is 12+5+13+15+14=59. So,

59+1=60/2=30.

sum of alphabetical positions of L, E, M, O and N is 12+5+13+15+14=59. So,

59+1=60/2=30.

6:

(a)

(a)

The

pattern here will be ‘abbaccabbacc’

pattern here will be ‘abbaccabbacc’

7:

(a)

(a)

The

pattern here will be ‘aababb’.

pattern here will be ‘aababb’.

8:

(c)

(c)

In

FUTURE, first two letters are reversed, last two letters are reversed and

middle two letters are unchanged. So, NATURE will be coded as ANTUER.

FUTURE, first two letters are reversed, last two letters are reversed and

middle two letters are unchanged. So, NATURE will be coded as ANTUER.

9:

(a)

(a)

In

TEA, the alphabetical positions of T, E and A are 20, 5 and 1. The positions

numbers are multiplied to get the code as 100. Similarly, FAT can be coded as

120.

TEA, the alphabetical positions of T, E and A are 20, 5 and 1. The positions

numbers are multiplied to get the code as 100. Similarly, FAT can be coded as

120.

10: (d)

2 A 8 D 5 C 9

B 3 = 2 × 8 – 5 + 9 ÷ 3 = 16 – 5 + 3 = 14

B 3 = 2 × 8 – 5 + 9 ÷ 3 = 16 – 5 + 3 = 14

11: (b)

12: (c)

13: (c)

Out of 60 students, if number of boys is double of

number of girls, then there are 40 boys and 20 girls in the class. Since

Kapil’s rank is 10

remaining 17 girls are below him in rank. Similarly, out of his 10

rank, 3 are girls who are ahead of him, then there are 7 boys (including Kapil)

till 10

number of girls, then there are 40 boys and 20 girls in the class. Since

Kapil’s rank is 10

^{th}and there are 3 girls ahead of him, thenremaining 17 girls are below him in rank. Similarly, out of his 10

^{th}rank, 3 are girls who are ahead of him, then there are 7 boys (including Kapil)

till 10

^{th}rank. Therefore, there are 33 boys below him in rank.
14: (d)

Out of 60 students, if number of boys is double of

number of girls, then there are 40 boys and 20 girls in the class. Since

Kapil’s rank is 10

remaining 17 girls are below him in rank.

number of girls, then there are 40 boys and 20 girls in the class. Since

Kapil’s rank is 10

^{th}and there are 3 girls ahead of him, thenremaining 17 girls are below him in rank.

15: (d)

16: (a)

17: (d)

18:

(b)

(b)

19: (c)

20: (d)

1-b

2-a

3-c

6-a

8-c

9-a

10-d

11-b

13-c

14-d

15-d

16-a

17-d

18-b

19-b

20-d

1-b

2-a

3-c

6-a

8-c

9-a

10-d

11-b

13-c

14-d

15-d

16-a

17-d

18-b

19-b

20-d

1-b

3-c

5-b

7-b

8-c

9-a

10-d

11-b

12-c

15-d

16-a

17-d

18-b

19-c

20-d

1-b

3-c

5-b

7-b

8-c

9-a

10-d

11-b

12-c

15-d

16-a

17-d

18-b

19-c

20-d

1-b

2-a

3-c

4-a

5-b

7-a

8-c

9-a

10-d

11-b

12-c

13-c

14-d

15-d

16-a

17-d

18-b

19-b

20-a

1-b

2-a

3-c

4-a

5-b

7-a

8-c

9-a

10-d

11-b

12-c

13-c

14-d

15-d

16-a

17-d

18-b

19-b

20-a

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Quant Quiz For SSC Exam

http://www.sscadda.com/2015/03/quant-quiz-for-ssc-exam_7.html

solution for question 12?

plz explain 12th..

plz explain 12th ques..

12th?

in my way 12 is diff b/w last digits of two nos

63@81—>3-1 apply to all

17. 10+(8*4)=42

20.go through options which code/option gives the word "POSE" it is the ans

Question no. 17

8×4+10=42,

6×8+8=56,

8×10+12=92 Answer

question no.12

take only unit digits

3 -1 = 2;

4 -1 = 3,

then 9-1 = 8

anyone explain first question

Hello Vikas

In this question

Rules is opposite pairs of Alphabet

F = 6,and U = 21s the opposite pair of F

So 27 – 6 = 21

H = 8 and S = 19 is the opposite pair of H

So 27 – 8 = 19

Similarly ,

M = 13 and N = 14 is the opposite pair of M

O = 14 and L= 12 is the opposite pair of N

12. If

63 @ 81 = 2; => 63 is reversed 36 adn 81 reversed is 18 then 36/18 = 2

above is the rule of this question.

Plz explain question 18

Thanks Sir

how can you get b for question 19…pls explain..my answer is c…as it looks more its image..throw some light…and explain…