Quant Quiz For SSC Exam

1. The average age of 40 boys in a class
is 15. The average age of a group of 18 boys in the class is 16 and the average
age of an other 12 boys in the class is 14. What is the average age of the
remaining boys in the class?
(a) 15•25 years 
(b) 14.4 years
(c) 14•75 years 
(d) None of these


2. Ruby invested an amount of Rs. 5,800 for 2 years. At what rate of
compound interest will she get an amount of Rs. 6394•5 at the end of two years
?
(a) 5 p.c.p.a.  
(b) 4 p.c.p.a.
(c) 6 p.c.p.a.  
(d) 8 p.c.p.a.

3.
A boat covers a distance of 30 km downstream in 2 hours while it takes 6
hours to cover the same distance upstream. How much time the boat will take to
cover 90 km in still water?
(a) 6 hrs  
(b) 9 hrs
(c) 15 hrs  
(d) None of these


4.
A lent Rs 5000 to B for 2 years and Rs 3000 to C for 4 years on simple
interest at the same rate of interest and received Rs 2200 in all from both of
them as interest. The rate of interest is
(a) 5%  
(b) 7%
(c) 8%  
(d) None of these

5. Train A and B travel to a place at a speed of 35 and 55 km/h
respectively. If car B takes  hours  less time than A for the
journey, the distance of the place is_
(a) 300.25 km 
(b) 400 km
(c) 350.565 km 
(d) 336.875 km

6. Two numbers are such that if the first is subtracted from six times
the second, their difference becomes 71, and if the second be added to 7 times
the first , their sum becomes 62. The two numbers are
(a) 19, 7  
(b) 13, 7
(c) 7, 13  
(d)17, 3

7. How much will be the compound interest to be paid on a principal
amount of Rs 85,000/- after 3 years at the rate of 6 p.c.p.a?
(a) Rs 16623.36/- 
(b) Rs 16236.36/-
(c) Rs 16326.36/- 
(d) Rs 16632.36/-

8. Yesterday Mansi typed an essay of 5000 words at the speed of 60 words
per minute. Today she typed the same essay faster and her speed was 15% more
than yesterday. What is the approximate difference in the time she took to type
yesterday and the time she took to type today?
(a) 20 minutes 
(b) 30 minutes
(c) 10 minutes 
(d) 40 minutes

9. To Finish a work, B will take three times as long as A and C together
and C will take twice as long as A and B together. If the three persons A, B and
C together can finish the work in 20 days , then how long will A take to finish
the work alone?
(a) 30 days  
(b) 45 days
(c) 48 days   
(d) 60 days

10. A person drove a certain distance by car the speed of 35 km/h and
returned on cycle at the speed of 10 km/h, If the whole journey took 18 hours.
Then what distance did he drive on car?
(a) 80 km  
(b) 120 km
(c) 140 km  
(d) 150 km


ANSWERS WITH EXPLANATION :-
1. (b)
Total students are 40 × 15 = 600
So, 18 x 16 + (12 + 14) = 456
Left student is 10 and their average is =600-456= 144÷ 10=14.4

2. (a)
The interest in 2 years is 594.5 which is 10.25% of 5800. Hence the rate of interest is 5% p.a.

3. (b)
Upstream speed = 5 km/hr
Downstream speed = 15 km/hr
Speed of boat in still water = (5 + 15)/2 = 10 km/hr
Required time = 90/10 = 9 hrs

4. (d)
Let the rate of interest is=x
(X * 5000 * 2)/100 + (3000 * 4 * x)/100 = 2200
x = 10%

5. (d)
Let Car A takes t hrs to reach  the place
Distance is same,
35 t = 55(t – 7/2)
T = 77/8
Distance = 35 * 77/8 = 336.87 km

6. (c)
Let the number  be X and Y
Then 6y – x = 71 and 7x + y = 62
 Solving the equation
X = 7,  y = 13

7. (b)

C.I. = 85000 × (19.1016/100)
= Rs 16236.36 Approx.

8. (c)

Difference of time = 5000/60 − 5000/(60 * 1.15)
= 5000/60 − 5000/69
= 83.33 – 72.46
= 10 min (Approx.)

9. (c)
3*B’s daily work= (A+C)’s daily work
4*B’s daily work = (A+B+C)’s daily work = 1/20
B’s daily work = 1/80
2*C’s daily work = (A+B)’s daily work
3*C’s daily work = (A+B+C)’s daily work = 1/20
C’s daily work= 1/60
A’s daily work= 1/20 – (1/80 + 1/60) = 1/48
A can finish the work in 48 days.


10. (c)
Let the distance be x km
Time taken by car = x/35 and time taken on cycle = x/10
x/10 + x/35 = 18

x  = 140

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28 Comments

  1. Q9
    as B will take three times as long as A and C together
    means B is 3 times efficient as long as A+C
    since efficiency is inversely proportional to work
    (A+C)’s daily work=3*B’s daily work–(1)
    (A+B)’s daily work=2*C’s daily work –(2)
    (A+B+C)'s daily work=1/20—-(3)
    from eqn 1 & 3
    (B+3*B)'s daily work=1/20
    4*B=1/20 , B's daily work=1/80
    from eqn 2& 3
    C+2*C=1/20 3*C=1/20 C=1/60
    put the value of B & C in eqn 3
    A+1/80+1/60=1/20
    A’s daily work= 1/20 – (1/80 + 1/60) = 1/48
    A can finish the work in 48 days.

  2. both distances same na……..
    so, distance1=distance2

    i don't now……. 35t=55(t-1)

    20t=55
    t=11/4
    so……. distance= speed*time
    35*11/4=96.25 answer…….. check ur explantion and answr sir

  3. actually there is data missing in Q5

    it is written, If car B takes 7/2 hours less time than A for the journey

    since If car B takes 7/2 hours less time than A for the journey

    Tb=Ta-7/2
    d/55=d/35-7/2
    d/35-d/55=7/2
    20*d/35*55=7/2
    d=7*35*55/2*20
    d=336.875 km

  4. A person bought some oranges worth rs 36 from ecch of the 5 markets at rs 1 rs 1.5 rs 1.8 rs 2 and rs 2.25 per orange . what is the avg price of the orange. Will someone solve this question plz.

  5. Mam I have been asking you from 10 days regarding FCI please provide Technical paper. I have to fill the application and I have to decide to apply for which post, last 7 days to go for closing date

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