Quant Quiz For SSC CGL Exam

Q3. If 20% of (P + Q) = 50% of (P – Q), then P : Q = ?
(a) 5 : 7
(b) 7 : 5
(c) 7 : 3
(d) 7 : 8

Q5. If A = 1/4 B and B = 1/2 C, then find the value of A : B : C.
(a) 8 : 4 : 1
(b) 4 : 2 : 1
(c) 1 : 4 : 8
(d) 1 : 2 : 4
(e) None of these

Q7. If the average of eight consecutive even numbers be 93, then the greatest number among them is
(a) 86
(b) 98
(c) 100
(d) 102

Q8. The average of 11 results in 50. If the average of the first six results in 49 and that of the last six is 52, the sixth result is
(a) 48
(b) 50
(c) 52
(d) 56

Q10. A tradesman marks his goods at 20% above the cost price but allows purchasers a discount of 5%. What profit percent does he make?
(a) 14%
(b) 18%
(c) 16%
(d) 19%

Q11. A man sells his typewriter at 5% loss. If he sells it for Rs. 80 more, he gain 5%. The cost price of typerwriter is
(a) Rs. 1600
(b) Rs. 1200
(c) Rs. 1000
(d) Rs. 800

Q12. Two types of tea costing Rs. 180 and Rs. 280/kg should be mixed in the ratio so that the mixture obtained, sold at Rs. 320/kg to earn a profit of 20% is
(a) 1 : 13
(b) 2 : 13
(c) 3 : 13
(d) 4 : 13

Q13. On selling 17 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. the cost price (in Rs.) of a ball is
(a) 45
(b) 50
(c) 55
(d) 60

Q14. In a farm there are cows and hens. If heads are counted there are 180, if legs are counted there are 420. The number of cows in the farm is
(a) 150
(b) 30
(c) 130
(d) 50

Q15. The speeds of A and B are in the ratio 3 : 4. A takes 20 minutes more than B to reach a destination. In what time does A reach the destination?
(a) 4/3 hours
(b) 2 hours
(c) 5/3 hours
(d) 8/3 hours

SOLUTIONS

S7. Ans.(c)
Sol. (a+ (a + 1)  + (a + 3)  + (a + 5)  + (a + 7))/8 = 93
∴ a = 93
∴ a + 7 = 93 + 7 = 100
S8. Ans.(d)
Sol. Sixth result = 49 × 6 + 52 × 6 – 50 × 11
= 56
S9. Ans.(b)
Sol. Given that a = 20, b = 15
According to the formula,
Profit % = ((a – b)/b×100)%
= 5/15 × 100% = 100/3% = 331/3%

S13. Ans.(d)
Sol. SP of a ball = 720/17
According to question
17 CP – 17 SP = 5 CP
12 CP = 17 SP
CP = 17/12 × SP
CP = 17/12×720/17 = Rs. 60
CP = Rs. 60
S14. Ans.(b)
Sol. Let the number of cows and hens in the farm be x and y, respectively
Then, x + y = 180 …(i)
⇒ 4x + 2y = 420 
⇒ 2x + y = 210 …(ii)
Subtracting Equation (i) from Equation (ii)
x = 30
Hence, there are 30 cows in the farm
S15. Ans.(a)
Sol. Let the time taken by A be x hrs.
Then, time taken by B = (x-20/60) hrs
= (x-1/3) hrs
Ratio of speeds = Inverse ratio of time taken
3 : 4 = (x-1/3) : x 
⇒(3x-1)/3x=3/4
⇒ 3x = 4
⇒ x = 4/3 hrs = 11/3 hrs
∴ Required time = 4/3 hrs
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