**1. A car driver completes a 180 km trip in 4 hours. If he averages 50 km/h during the first 3 hours of trip, what was his speed in the final hour.**

**2. A and B start running towards each other at 6 km/h and 9 km/h respectively. What was the distance between them 15 minutes before they met?**

**3. On a journey across Mumbai, tourist bus average 10 km/hr for 20% of the time, 30 km/hr for 60% of it and 20 km/hr for the remainder. The average speed for the whole journey was:**

**4.The distance between two cities is 800 km. A motor car starts from the first city at the speed of 30 km/hr. At the same time, another car starts from the second city towards the first at the speed of 50 km/hr. The distance of the point from the first city where both the cars meet is:**

**5. A train travelling at the speed of 90 km/hr follows a goods train after 6 hours from a station and overtakes it in 4 hours. What is the speed of the train?**

**6. Two trains move from station A and station B towards each other at the speed of 50 km/hr and 60 km/hr. At the meeting point, the driver of the second train felt that the train has covered 120 km more. What is the distance between A and B?**

**7. Shan starts 3 minutes after Bonny from the same point, for a place at a distance of 4 (1/2) miles. Bonny on reaching her destination immediately returns and after walking a mile meets Shan. If Shan’s speed be a mile in 18 minutes, what is Bonny’s speed in miles per minute?**

**(a) 1/6**

**8.A Shatabdi Express train, owing to a defect in the engine, goes at 5/8 of its proper speed and arrives at 6.49 pm instead of 5.55 pm. At what hour did it start?**

**9.A hare pursued by a greyhound, is 50 of her own leaps ahead of him. While the hare takes 4 leaps, the greyhound takes 3 leaps. In one leap, the hare goes 1(3/4) metre and the greyhound 2(3/4) metres. In how many leaps will the greyhound overtake the hare?**

**10. A man walks a km in b hours. The time taken to walk 200 metres is**

**Answers and Solution:**

1. (d)

Distance in 3 hours = 50*3 = 150 km.

Speed in final hr = (180-150)/1 = 30 km/hr

2.(d)

3.(d)

Average speed = (v1t1+v2t2+v3t3)/(t+t2+t3)

= (10*.2+30*.6+20*.2)/1 = 24 km/hr.

4. (b)

Since time of travel for both car is same so

V1 = 30 km/hr

V2 = 50 km/hr

d1/d2 = v1/v2 = 3/5 => 3/8*800 = 300 km.

5.(c)

Goods train travel for 6 + 4 = 10 hrs. other train for 4 hrs,travel distance is same = v1t1 = v2t2

=> v1/v2 = t2/t1 = 10/4 = 5/2

Since v1 = 90 k/h => V2 = 36 km/hr

6. (a)

7. (d)

8. (d)

9. (a)

10.(c)

1 km in b/a hrs => 1000m in b/a hrs. => 200m in b/5a hrs.