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Quant Practice Test For SSC CGL 2016

1. (c)   Let C.P of these articles are CP_1  and CP_2
CP1×125/100=4000
CP1=4000/125×100
CP1=3200
Profit = 800 
Loss on 2nd Article = 800
CP2=4000+800=4800
Loss% =800/4800×100
=16 (2/3)%
                   

 

2. (b)    Percentage increases in price 
=(1.5/6)×100=25%
Percentage decreases in consumption = x%
25 – x –  (25x/100)=0
x(1+1/4)=25
x=20% decreases
3. (c)   S1=5
S2 = 3
S1×3/5 = S2
T1/T2 =3/5]  difference of 2
Time difference = 15 + 9 
2x = 24 min 
x = 12 min 
T_1=3×12= 36 min 
T_2=5×12 = 60 min 
Distance = 3 × 1
= 3 km. 
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21.                     Side
= 10 m
                    Area
= 10 × 5 = 50 m
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