Dear maths lovers, Let your practice begins in minuteness but ends in magnificence.It is impossible to **study maths** properly by just reading and listening. So, practise, practise & more practise. For that, we are providing here **Quant Quiz **of 15 questions on Ratio and Proportion, in accordance with the syllabus of SSC CGL.We have also provided **Study Notes and quizzes **on all the topics.

Q1. A man ordered 4 pairs of black socks and some pairs of brown socks. The price of a black socks is double that of a brown pair. While preparing the bill the clerk interchanged the number of black and brown pairs by mistake which increased the bill by 50%. The ratio of the number of black and brown pairs of socks in the original order was:

(a) 2: 1

(b) 1: 4

(c) 1: 2

(d) 4: 1

Q2. The ratio of the present age of two brothers is 1: 2 and 5 years back, the ratio was 1: 3. What will be the ratio of their age after 5 years?

(a) 1: 4

(b) 2: 3

(c) 3: 5

(d) 5: 6

Q3. The sum of the age of a father and his son is 100 years now. 5 years ago their age was in the ratio of 2: 1. The ratio of the age of father and son after 10 years will be

(a) 5: 3

(b) 4: 3

(c) 10: 7

(d) 3: 5

Q4. Ram is 40 years old and Ritu is 60 years old. How many years ago was the ratio of their ages 3: 5?

(a) 10 years

(b) 20 years

(c) 37 years

(d) 5 years

Q5. Four years ago, the ratio of the age of A and B was 2: 3 and after four years it will become 5: 7. Find their present age.

(a) 36 years and 40 years

(b) 32 years and 48 years

(c) 40 years and 56 years

(d) 36 years and 52 years

Q7. The ratio of the ages of a father and his son 10 years hence will be 5: 3, while 10 years ago, it was 3: 1. The ratio of the age of the son to that of the father today, is

(a) 1: 2

(b) 1: 3

(c) 2: 3

(d) 2: 5

Q8. My grandfather was 9 times older than me 16 years ago. He will be 3 times of my age 8 years from now. Eight years ago, the ratio of my age to that of my grandfather was

(a) 3: 8

(b) 2: 5

(c) 1: 2

(d) 1: 5

Q9. Two numbers are in the ratio 2: 3. If 2 is subtracted from the first and 2 is added to the second, the ratio becomes 1: 2. The sum of the numbers is:

(a) 30

(b) 28

(c) 24

(d) 10

Q10. The sum of three numbers is 68. If the ratio of the first to the second be 2: 3 and that of the second to the third be 5: 3, then the second number is

(a) 30

(b) 58

(c) 20

(d) 48

Q11. When a particular number is subtracted from each of 7, 9, 11 and 15, the resulting numbers are in proportion. The number to be subtracted is:

(a) 1

(b) 2

(c) 3

(d) 5

Q12. The ratio between a two-digit number and the sum of the digits of that number is 4: 1. If the digit at the unit’s place is 3 more than the digit at the ten’s place, then the number is

(a) 47

(b) 69

(c) 36

(d) 25

Q13. The ratio of the number of boys and girls of a school with 504 students is 13: 11. What will be the new ratio if 12 more girls are admitted?

(a) 91: 81

(b) 81: 91

(c) 9: 10

(d) 10: 9

Q14. In a school having roll strength 286, the ratio of boys and girls is 8: 5. If 22 more girls get admitted into the school, the ratio of boys and girls becomes

(a) 12: 7

(b) 10: 7

(c) 8: 7

(d) 4: 3

Q15. The number of students in three classes are in the ratio 2: 3: 4. If 12 students are increased in each class, this ratio changes to 8: 11: 14. The total number of students in the three classes at the beginning was

(a) 162

(b) 108

(c) 96

(d) 54

**Solutions**

S13. Ans.(a)

Sol. Boys: Girls

⇒ 13: 11

12 more girls are added. It means the number of boys is same.

So, from option check multiple of 13

Thus, option (a) is correct 91: 81

S14. Ans.(d)

Sol. Boys: girls

8: 5

Total students = 286

So, 13r → 286

1r → 22

Now, 22 more girls are added,

So, ratio must be 8: 6

= 4 : 3