**Q1. By selling an article for Rs. 102, there is a loss of 15%. When the article is sold for Rs. 134.40, the net result in the transaction is:**

(a) 12% gain

(b) 12% loss

(c) 10% loss

(d) 15% gain

**Q2. A shopkeeper sold his goods at half the list price and thus lost 20%. If he had sold on the listed price, his gain percentage would be**

(a) 20%

(b) 35%

(c) 60%

(d) 72%

**Q3. A builder purchase 25 windows at 25% off the total price of Rs. 120000. If the builder receives an additional discount of Rs. 7500 for the purchase, then the cost of each window is-**

(a) Rs. 3100

(b) Rs. 3200

(c) Rs. 3300

(d) Rs. 3400

**Q4. In a coconut grove, (x + 2) trees yield 60 nuts per year, x trees yield 120 nuts per year, and**

**(x – 2) trees yield 180 nuts per year. If the average yield per year per tree be 100, find the value of x.**

(a) 4

(b) 2

(c) 8

(d) 6

**Q5. Visitors to a show were charged Rs. 15.00 each on the first day, Rs. 7.50 on the second, Rs. 2.50 on the third day. Visitors total attendance for three days were in the ratio 2: 5: 13. Find out the average charge per visitor for the entire show.**

(a) Rs. 7

(b) Rs. 5

(c) Rs. 9

(d) Rs. 11

**Q6. If a man rows 4 km downstream in 3 hours and 2 km upstream in 2 hours, then how long will he take to cover 8 km in stationary (still) water?**

(a) 5 hours

(b) 9 hours

(c)8 hours

(d) none of these

S6. Ans.(d)

Sol. Distance

covered in downstream = 4 km

covered in downstream = 4 km

Time taken

in downstream = 3 hours.

in downstream = 3 hours.

Rate of

downstream = distance / time = a = 4km / 3 hours = 4/3 km/hr.

downstream = distance / time = a = 4km / 3 hours = 4/3 km/hr.

Distance

covered in upstream = 2 km

covered in upstream = 2 km

Time taken

in upstream = 2 hours.

in upstream = 2 hours.

Rate of

upstream = distance / time = b = 2 km / 2 hours = 1 km/hr.

upstream = distance / time = b = 2 km / 2 hours = 1 km/hr.

Speed in still

water = (a + b)/2 = (1/2)(4/3 + 1) km/hr = (1/2)(4 + 3)/3 = 7/6 km/hr.

water = (a + b)/2 = (1/2)(4/3 + 1) km/hr = (1/2)(4 + 3)/3 = 7/6 km/hr.

Time Taken

to cover 8 km in still water = distance / speed = 8 x 6/7 = 48 / 7 = 7 hours

(approximately).

to cover 8 km in still water = distance / speed = 8 x 6/7 = 48 / 7 = 7 hours

(approximately).

**Q7. The speed of a boat in still water is 30 km/hr and the rate of current is 12 km/hr. The distance traveled upstream in 20 minutes is –**

(a) 6 km/hr

(b) 5 km/hr

(c) 9 km/hr

(d) 8 km/hr

**Q8. Sandeep can row a certain distance downstream in 5 hours and return the same distance in 7 hours. If the stream flows at the rate of 2 km per hour. Find the speed of Sandeep in still water.**

(a) 14 km/h

(b) 15 km/h

(c) 13km/h

(d) 12 km/h

S8. Ans.(d)

Sol. In one

direction he will go by downstream and return with upstream and in both cases

distance is same

direction he will go by downstream and return with upstream and in both cases

distance is same

Downstream

distance = Upstream distance

distance = Upstream distance

(u + 2) 5 =

(u – 2) 7

(u – 2) 7

u = 12 km/h

**Q9. The rate of flow of river water is 4 km/hr. A boat goes 6 km and back to the starting point in 2 hours. Find the speed of the boat in still water.**

(a) 6 km/hr

(b) 8 km/hr

(c) 9 km/hr

(d) 10 km/hr

**Q10. A man can row 30 km upstream and 44 km downstream in 10 hrs. Also, he can row 40 km upstream and 55 km downstream in 13 hrs. Find the rate of the current(v) and the speed of the man(u) in still water.**

(a) u = 5, v = 4

(b) u = 6, v = 5

(c) u = 8, v = 3

(d) None of these

**Q11. A circle and a rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. The area of the circle is [Take π=22/7]**

(a) 125 cm

^{2}
(b) 230 cm

^{2}
(c) 550 cm

^{2}

(d) 616 cm

^{2}^{}