**Q1. If it is possible to form only one such number with the third, the sixth and the seventh digits of the number 7394261 which is the perfect square of a two-digit even number, which of the following will be the second digit of that two-digit even number?**

(a) 6

(b) 4

(c) 2

(d) No such number can be formed

**Ans.(b)**

**Sol. 169, 196 and 961, which are the squares of 13, 14 and 31 Respectively.**

**So, 14 is even number**

**Second digit is ‘4’**

**Q2. In a row of 40 children, Y is eleventh from the right end and there are fifteen children between Y and P. What is P’s position from the left end of the row?**

(a) Thirteenth

(b) Fifteenth

(c) Fourteenth

(d) Cannot be determined

**Ans.(c)**

**Sol. Y’s position = 11th from right**

**P’s position = (11 + 15 + 1 = ) 27th from right**

**= (40 – 27 + 1 )= 14th from left**

**Q3. Megha drives 10 km towards South, takes a right turn and drives 6 km. She then takes another right turn, drives 10 km and stops. How far is she from the starting point?**

(a) 10 km

(b) 4 km

(c) 6 km

(d) 12 km

**Q4. Nikhil correctly remembers that Neha’s birthday is before Friday but after Tuesday. Deepak correctly remembers that Neha’s birthday is after Wednesday but before Saturday. On which of the following days does Neha’s birthday definitely fall?**

(a) Monday

(b) Tuesday

(c) Wednesday

(d) Thursday

**Ans.(d)**

**Sol. According to Nikhil, Neha’s birthday falls on Wed or Thu …(i)**

**According to Deepak, Neha’s birthday falls on Thu or Fri …(ii)**

**From (i) and (ii), Neha’s birthday falls on Thursday.**

**Q5. Among P, Q, R, S and T each reaching school at a different time, R reaches before S and P and only after Q. T is not the last to reach school. Who among them reached school last?**

(a) S

(b) P

(c) R

(d) Data inadequate

**Ans.(d)**

**Sol. The sequence is**

**Q > R > T, S, P**

**Q6. Three positions of a cube are as shown below :**

**The figure on the face opposite the triangle is the :**

(a) pentagon

(b) circle

(c) question mark

(d) rectangle

**Q7. What will come in place of ‘?’**

**15, 24, 43, 71, (?), 154**

(a) 114

(b) 108

(c) 100

(d) 140

**Ans.(b)**

**Sol. The pattern of the number series is as given below:**

**15 + 9 = 24**

**24 + 19 (= 10 + 9) = 43**

**43 + 28 (= 19 + 9) = 71**

**71 + 37 (= 28 + 9) = 108**

**108 + 46 (= 37 + 9) = 154**

**Q8. What will come in place of ‘?’**

**12, 18, 36, (?) , 360, 1386**

(a) 112

(b) 102

(c) 135

(d) 140

**Ans.(b)**

**Sol. The pattern of the number series is as given below:**

**12 × 4 – 30 = 48 – 30 = 18**

**18 × 4 – 36 = 72 – 36 = 36**

**36 × 4 – 42 = 144 – 42 = 102**

**102 × 4 – 48 = 408 – 48 = 360**

**360 × 4 – 54 = 1440 – 54 = 1386**

**Q9. Which one of the letters when sequentially placed at the gaps in the given letter series shall complete it?**

**xx__yz__xyz__xx__yyz__z**

(a) y y x y z

(b) y z x y z

(c) y z y y z

(d) y x x y z

**Ans.(b)**

**Sol. The series is xxyyzz/xyz/xxxyyyzzz.**

**DIRECTIONS (10 – 12): The questions below are to be answered on the basis of the three views of a cube given as follows :**

**Q10. Which number is on the face opposite to 6?**

(a) 3

(b) 2

(c) 1

(d) 4

**Ans.(c)**

**Sol. The number on the opposite to 6 is 1 because 4, 3, 2 and 5**

**are adjacent faces of 6.**

**Q11. Which number is on the face opposite to 4?**

(a) 2

(b) 3

(c) 6

(d) 1

**Ans.(a)**

**Sol. The number opposite to 4 is 2 because 5, 1, 6 and 3**

**are adjacent faces of 4**

**Q12. Which number is at the bottom face of figure 3?**

(a) 3

(b) 2

(c) 5

(d) 1

**Ans.(c)**

**Sol. 6 -> 1**

**4 -> 2**

**So opposite to 3 is 5.**

**Q13. In a certain code WEAK is written as 5%9$ and WHEN is written as 5*%7. How HANK written in that code?**

(a) *9$7

(b) 9*$7

(c) *97$

(d) 9*7$

**Q14. ‘Army’ is related to ‘Land’ in the same way as ‘Navy’ is related to _____.**

(a) Ships

(b) Battle

(c) Water

(d) Admiral

**Ans.(c)**

**Sol. The first is the force fighting on/in the second.**

**Q15. 08 : 28 : 15 : ?**

(a) 67

(b) 65

(c) 123

(d) 15

**Ans.(b)**

**Sol.**

**First**

term = 3

– 1.

term = 3

^{2}– 1.

**Second**

term = 3

+ 1

term = 3

^{3}+ 1

**Third**

term = 4

– 1

term = 4

^{2}– 1

**Fourth term = 4**

1

^{3}+1