Q1. A and B together can do a work in 8 days, B and C together in 6 days, while C and A together in 10 days. If they all work together, the work will be completed in
Q2. A is twice efficient than B; and together they finish a work in 16 days. In how many days can it be done by A separately?
(a) 24 days
(b) 22 days
(c) 23 days
(d) None of these
Q3. A and B together can complete a work in 8 days and B and C together in 12 days. All of them together can complete the work in 6 days. In how much time will A and C together complete the half the work?
(a) 4 days
(b) 10 days
(c) 2 days
(d) 8 days
Q4. A builder decided to build a house in 40 days. He employed 100 men in the beginning and 100 more after 35 days and completed the construction in stipulated time. If he had not employed the additional men, how many days behind schedule would it have been finished?
(a) 5 days
(b) 6 days
(c) 8 days
(d) 10 days
Sol. For the last 5 days 200 men worked in place of 100 men,
200 × 5 = 100 × x
x = 10 days (This means 100 men would have taken 10 days)
hence, they will take 5 day more than stipulated time
Q5. 10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
(d) None of these
Sol. ∴ 10 women can complete the work in 7 days.
∴ 70 women can complete the work in 1 day.
∴ 10 children can complete the work in 14 days.
∴ 14o children can complete the work in 1 day.
∴ 70 women = 140 children
∴ 1 women = 2 children
∴ 5 women + 10 children
(10 + 10) children = 20 children
Now, 140 children can complete the work in 1 day
∴ 20 children can complete in 140/20 = 7 days.
Q6. In an examination, the number of those who passed and the number of those who failed were in the ratio 25 : 4. If five more had appeared and the number of failures was 2 less than earlier, the ratio of passers to failures would have been 22 : 3. The number who appeared at the examination, is
Sol. Let the number of passed student and that of failed students be 25x and 4x respectively.
According to the question, if 5 more had appeared i.e. 25x + 4x + 5
= 29x + 5, number of failure was 2 less i.e. 4x – 2, then passed/failures=22/3
Passed = appeared – failed
((29x +5)-(4x – 2))/(4x – 2)=22/3
⇒ (29x – 4x + 5 + 2)/(4x – 2)=22/3
⇒ (25x + 7)/(4x – 2)=22/3
⇒ 75x + 21 = 88x – 44
⇒ 21 + 44 = 88x – 75x
⇒ 13x = 65
x = 5
Number of students who appeared = 29x
= 29 × 5 = 145
Q7. The ratio of A to B is 4 : 5 and that of B to C is 2 : 3. If A equals 800, C equals
Sol. A:B=4:5 = 8:10
B:C=2:3 = 10:15
Q8. Ratio of earning of A and B is 8 : 9 respectively. If the earnings of A increase by 50% and the earnings of B decrease by 25%, the new ratio of their earnings becomes 16 : 9 respectively. What are A’s earnings?
(a) Rs. 37,000
(b) Rs. 28,500
(c) Rs. 22,000
(d) Can’t be determined
Sol. Let the earnings of A and B be 8x & Rs. 9x respectively.
Now, after changes in their earnings,
A’s earning =150/100×8x = Rs. 12x
B’s earning =75/100×9x= Rs. 27x/4
From above data ,We cannot find the answer of the given question
Hence, answer will be can’t be determine
Q9. A and B entered into a partnership, investing Rs. 16,000 and Rs. 12,000 respectively. After 3 months, ‘A’ withdrew Rs. 5000, while ‘B’ invested Rs. 5000 more. After 3 month more, C joins the business with a capital of Rs. 21,0000. After a year, they obtained a profit of Rs. 26,400. By what amount does the profit of B exceed the share of C?
(a) Rs. 3600
(b) Rs. 3800
(c) Rs. 4600
(d) Rs. 4800
Q10. A, B and C start a business by investing Rs. 20,000 each. After 5 months A withdraws Rs. 5,000, B withdraws Rs. 4,000 and C invests Rs. 6,000 more. If at the end of year the profit was Rs. 69,900 then what will be B’s share?
(a) Rs. 20,500
(b) Rs. 21,200
(c) Rs. 28,200
(d) Rs. 19,621
Q11. There are three members in a family, mother, father and son. The average age of the three members was 42 years on the day of their son’s marriage. After 6 years of the marriage, the average age of the family will be 36 years when a grandson was born after 2 years of the marriage. Find the age of the daughter-in-law at the time of marriage.
(a) 26 yrs.
(b) 27 yrs.
(c) 28 yrs.
(d) 29 yrs.
Q12. If 6 years are subtracted from the present age of Randheer and the remainder is divided by 18, then the present age of his grandson Anup is obtained. If Anup is 2 years younger to Mahesh whose age is 5 years, then what is the age of Randheer?
(a) 96 years
(b) 84 years
(c) 48 years
(d) 60 years
Sol. Mahesh present age = 5 years
So, Anup’s present age = (5 – 2) = 3 years
According to question, (R – 6)/18=3
R = 18 × 3 + 6 = 54 + 6 = 60 years
Q13. Nine litres are drawn from a cask full of water and it is then filled with milk, Nine litres of mixture are drawn and the cask is again filled with milk. The quantity of water now left in the cask to that of the milk in it is 16 : 9. How much does the cask hold?
(a) 40 litres
(b) 45 litres
(c) 50 litres
(d) 55 litres
Q14. If 2 kg of metal, of which 1/3 is zinc and the rest is copper, be mixed with 3 kg of metal, of which 1/4 zinc and the rest is copper, what is the ratio of zinc to copper in the mixture?
(a) 13 : 42
(b) 17 : 43
(c) 19 : 43
(d) 15 : 42
Sol. Quantity of zinc in the mixture
=2(1/3)+3(1/4)=2/3+3/4=( 8 + 9)/12=17/12
Quantity of copper in the metal
∴ ratio =17/12 ∶43/12=17∶43
Q15. A man has 60 pens. He sells some of these at a profit of 12% and the rest at 8% loss. On the whole, he gets a profit of 11%. How many pens were sold at 12% profit.