**1.Two pipes can fill a cistern in 3 hours and 4 hours respectively and a waste pipe can empty it in 2 hours. If all the three pipes are kept open. Then the cistern will be filled in :**

**2.A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days, B had to leave and A alone completed the remaining work. The whole work was completed in :**

**3.An article is sold at a profit of 20%. If it had been sold at a profit of 25%, it would have fetched Rs. 35 more. The cost price of the article is :**

**4.A tradesman sold an article at a loss of 20%. If the selling price had been increased by Rs. 100, there would have been a gain of 5%. The cost price of the article was :**

**5.If the ratio of areas of two squares is 225 : 256, then the ratio of their perimeters is :**

**6.The percentage increase in the area of a rectangle, if each of its sides is increased by 20%, is :**

**7.A number is increased by 20% and then again by 20%. By what per cent should the increased number be reduced so as to get back the original number?**

**8.A boy, after giving away 80% of his pocket money to one companion and 6% of the remainder to another, has 47 paise left with him. How much pocket money did the boy have in the beginning?**

**9.If the compound interest on a sum for 2 years at 12(1/2)% per annum is Rs. 510, the simple interest on the same sum at the same rate for the same period of time is :**

**10.5 persons can prepare an admission list in 8 days working 7 hours a day. If 2 persons join them so as to complete the work in 4 days, they need to work per day for :**

**Answers and Solution:**

1.(4)

Part of the cistern filled in 1 hour

= 1/3 +1/4 – 1/2

= 1/12

Hence ,the cistern will be filled in 12 hours.

2.(3)

Work done by(A+B) in 1 day = 1/15+1/10 = = 1/6

so (A+B)’s 2 days work 2/6 = 1/3

Remaining work = 1 – 1/3 = 2/3

This part is done by A alone

1 work is done by A in 15 days

so 2/3 work is done in 15*2/3= 10 days.

Required number of days= 12 days

3.(2)

Let the cost price be Rs.x

so 125% of x – 120% of x = 35

x = 700

4.(3)

Let C.P of article be Rs.x.

so 105% of x – 80% of x = 100

= 25% of x = 100

so x = 400

5.(3)

6.(3)

Net Effect = (20+20+(20*20)/100)%

= 44%

7.(1)

Let the number be 100.

After 20% increase,number = 120

number = 120*120/100 = 144

so percent decrease = 44/144*100 = 30(5/9)%

8.(2)

Let the boy had Rs.x

Money given to first companion = 80% of x = 4x/5

Remaining money = x – 4x/5 = x/5

Money given to another companion = 6/100*x/5 = 3x/250

Remaining money = x/5 – 3x/250

so 47x/250 = 47/100

x = Rs. 2.50

9.(2)

10.(1)

persons 7 : 5

:: 7 : x

Days 4 : 8

so 7 * 4 * X = 5*8*7

so x = 10 days