MISSION CGL MAINS 2015 : Advanced Quant Quiz

1.The diagonal of a square is 42 cm. The diagonal of another square,whose area is double that of the first square, is
(1) 8√2
(2) 16 cm
(3) 32 cm
(4) 8 cm

2. The volume of cuboide is twice that of a cube. If the dimension of the cuboid are 9 cm, 8cm and 6cm, the total surface area of the cube is
(1) 72 cm^2
(2) 216 cm^2
(3) 432 cm^2
(4) 108 cm^2
3. Base of a right prism is an equilateral triangle of side 6 cm.If the Volume of the prism is 1083 cc,its height is
(1) 9 cm
(2) 10 cm 
(3) 11 cm 
(4) 12 cm
4. The ratio of a radii of two right circular cylinder is 2:3 and their heights are in the ratio 5:4 .The ratio of their curved surface area is
(1) 5 : 6
(2) 3 : 4
(3) 4 : 5
(4) 2 : 3
5. If the length of a rectangle is increased by 50 % and the breath is decreased by p per cent to maintain the same area, then p equals
(1) 33(1/4)
(2) 32(1/2)
(3) 33(1/3)
(4) 35(1/3)
6.Sphere A and B have their radii 40 cm and 10 cm respectively.Ratio of  surafce area of A to  to the surafce area of B is.
(1) 16:1
(2) 1:16
(3) 4:1

(4) 8:1





Answers……..
1(4)
Diagonal of Square = 42 cm.
So Area of square = 1/2 (42)^2
=> 1/2*16*2 = 16 cm^2
Area of other square  = 2*16 = 32 cm^2

so Diagonal = 8 cm.

2.(2)
Volume of cuboide = 9*8*6 = 432 cm^2
According to the question ,
volume of cube = 432/2 = 216 cm^3
So Edge of cube = 6 cm
So Total surface area of cube = 6*(6)^2 = 216 cm^2

3(4).
Area of base = 3/4*(side)^2
3/4*6*6 = 93 sq.cm.
so volume of the prism  = Area of base*height
=> 1083 = 93*h
=> h = 1083/93 = 12 cm.

4.(1)
First cylinder   second cylinder
r1 = 2r            r2 = 3r
h1 = 5h            h2 = 4h
so Required ratio = 2pr1h1 : 2pr2h2
= 2*5 : 3*4 = 5 : 6
5.(3)
Area remains same.
so 50 – p – (50*p)/100 = 0
=> 100 – 2p – p = 0 => 3p = 100
=> p = 100/3 =33(1/3)
6.  (1)
7.  (c)
8.  (a)
9.  (c)
10.(a)

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