**1.The banker’s discount on Rs. 1600 at 15% per annum is the same as true discount on Rs. 1680 for the same time and at the same rate. The time is:**

**2.The banker’s discount on a sum of money for 1 years is Rs. 558 and the true discount on the same sum for 2 years is Rs. 600. The rate percent is:**

**3. The present worth of a sum due sometimes hence is Rs.5760 and the baker’s gain is Rs.10. What is the true discount?**

**4. A bill for Rs. 3000 is drawn on 14th July at 5 months. It is discounted on 5th October at 10%. What is the Banker’s Discount?**

**5.Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?**

**6.If simple interest on a certain sum of money for 8 years at 4% per annum is same as the simple interest on Rs. 560 for 8 years at the rate of 12% per annum then the sum of money is**

**7.The compound interest on a sum for 2 years is Rs. 832 and the simple interest on the same sum for the same period is Rs. 800. The difference between the compound and simple interest for 3 years will be**

**8.John invested money in two schemes A and B offering compound interest @ 5 p.c.p.a. and 10 p.c.p.a. respectively. If the total amount of interest accrued through two schemes together in two years was Rs. 2075 and the total amount invested was Rs. 15,000, find out the amount invested in Scheme A?**

**9. If the cost of x metres of wire is d rupees, then what is the cost of y metres of wire at the same rate?**

**10.A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. If the smaller wheel has made 21 revolutions, what will be the number of revolutions made by the larger wheel?**

**ANSWERS WITH SOLUTION:**

**1(B)**Explanation:

S.I. on Rs. 1600 = T.D. on Rs. 1680.

Rs. 1600 is the P.W. of Rs. 1680, i.e., Rs. 80 is on Rs. 1600 at 15%.

Time = ((100 x 80)/(1600 x 15)year = 1/3 year = 4 months.

**2( C)**Explanation:

B.D. for 3/2 years = Rs. 558.

B.D. for 2 years = (558 x 2/3 x 2)

= Rs. 744

T.D. for 2 years = Rs. 600.

Sum = (B.D. x T.D)/(B.D. – T.D) = Rs. (744 x 600/144) = Rs. 3100.

Thus, Rs. 744 is S.I. on Rs. 3100 for 2 years.

Rate = (100 x 744)/(3100 x 2)%= 12%

**3(D)**

**4( A)**Explanation :F = Rs. 3000

R = 10%

Date on which the bill is drawn = 14th July at 5 months

Nominally Due Date = 14th December

Legally Due Date = 14th December + 3 days = 17th December

Date on which the bill is discounted = 5th October

Unexpired Time

= [6th to 31st of October] + [30 Days in November] + [1st to 17th of December]

= 26 + 30 + 17 = 73 Days

=73/365 year = 1/5 year

BD = Simple Interest on the face value of the bill for unexpired time =FTR/100

=3000×1/5×10/100 =30×1/5×10 = Rs. 60

**5( A)**Explanation :

Let the investment in scheme A be Rs.x

and the investment in scheme B be Rs.(13900 – x)

We know that SI = PRT/100

Simple Interest for Rs.x in 2 years at 14% p.a. = x×14×2/100=28x/100

Simple Interest for Rs.(13900 – x) in 2 years at 11% p.a

. =(13900-x)×11×2/100=22(13900-x)/100

Total interest = Rs.3508

28x/100+22(13900-x)/100=3508

28x+305800-22x=350800

6x=45000

x=450006=7500

Investment in scheme B = 13900 – 7500 = Rs.6400

**6(D)**Explanation :

Let the sum of money be x

then

x×4×8/100=560×12×8/100

x×4×8=560×12×8

x×4=560×12

x=560×3=1680

**7(D)**Explanation :

Given that simple interest for 2 years is Rs.800

i.e., Simple interest for 1st year is Rs.400

and simple interest for 2nd year is also Rs.400

Compound interest for 1st year will be 400

and Compound interest for 2nd year will be 832 – 400 = 432

you can see that compound interest for 2nd year is more than simple interest for 2nd year by 432 – 400 = Rs.32

i.e, Rs. 32 is the interest obtained for Rs.400 for 1 year

Rate, R = 100×SI/PT= (100×32)/(400×1)= 8%

Difference between compound and simple interest for the 3rd year

= Simple Interest obtained for Rs.832

=PRT/100=832×8×1/100= Rs. 66.56

Total difference between the compound and simple interest for 3 years

= 32 + 66.56 = Rs.98.56

**8(A)**Explanation :

Let the investment in scheme A be Rs.x

Then the investment in scheme = Rs.(15000-x)

Compound interest for Rs.x = P(1+R/100)^T-P= x(1+5/100)^2-x

Compound interest for Rs. (15000-x) = P(1+R/100)^T-P=

(15000-x)(1+10/100)^2-(15000-x)

Total compound interest = x(1+5/100)^2-x+(15000-x)(1+10/100)^2-(15000-x)

=x(1+10/100+25/10000)-x+(15000-x)(1+20/100+100/10000)-(15000-x)

=x(10/100+25/10000)+(15000-x)(20/100+100/10000)

=1025x/10000+(15000-x)((2100/10000)

=1025x/10000+15000×2100/10000-2100x/10000

=-1075x/10000+3150

Given that total compound interest = Rs. 2075

-1075x/10000+3150=2075

=>1075x/10000=1075

=>x/10000=1

=>x=10000

i.e, Amount invested in Scheme A = Rs. 10000

**9(C)**Explanation :

cost of x metres of wire = Rs. d

cost of 1 metre of wire = Rs.(d/x)

cost of y metre of wire = Rs.(y×d/x)=Rs. (yd/x)

**10(D)**Explanation :

Let the number of revolutions made by the larger wheel be x

More cogs, less revolutions (Indirect proportion)

Hence we can write as

Cogs 6 : 14} :: x : 21

6×21= 14×x

6×3 = 2×x

3×3 = x

x=9

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Mam…I secured 305 marks (in both Tier 1 and Tier 2)….Can I be called for SSC CGL Interview ??? Please mam…enquire and reply me

Reasoning Quiz For SSC Exam

http://www.sscadda.com/2015/04/reasoning-quiz-for-ssc-exam.html

Pls solve this problem

A cylindrical vessel of diameter 12 cm contains some water . if two spheres of radii 6 cm each are lowered into the water until they are completely immersed then the water level in the vessel will rise by?

A. 4

B. 9

C. 12

D.6

Please provide me the solution for this problem .

yr cat tejesh

ANS– 16 cm

But it is not there man

wt is correct ans

I don't know exactly , I think 4 is given in some of the sites, what is the formula

OBC Category (AP)

I am getting 375 but no hopes, wait for the results

let rise of water b H

r1 = radius of cylinder=12/2=6 cm

r2=radius of sphere= 6 cm

then vol of cylinder=2*vol of sphere

pie*(r1^2)*H =2*(4/3)pie*(r2)^3

(r1^2)*H =2*(4/3)*(r2)^3

6*6 *H= 2*(4/3)*6*6*6

H=2*(4/3)*6

H=16 cm

if u take radius of cylinder 12 cm

then H=4 cm

may b in Q in place of diameter, there is radius

last yr cut off for obc was 390

and this yr it will increase 10-15 marks

hmmm…okay and thanks dear for information

hmmm…

don't b sad bro try yr best in CGL 2015 .. i best wishes is with u

Just now I got the answer

For this formula is

Rice in water level = volume of sphere/area of cylinder

=2*4/3*pi*6*6*6/(pi*12*12).

if u take radius of cylinder = 12 cm then ANS will b 4 cm

This question is given in SSC cgl tire2 2015 , same model given in DC cgl 2012 paper, if u have kiran model papers check it , u will get good idea

Sorry yar, by mistake I gave it diameter as 12 ,but it is 24, sorry

Thank you once again dear

i hv practice work book of kiran's pub

Good , how many marks u r getting in cgl14 ?

hmm

i have not checked

Why shadow?

don't know… :))

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Hw i can guide u ..???

I gave last year'Sbi po before that i applied but could nt gave bcz exam centre was vry distant.

but u had given last yr na…..

it means u hv some knowledge abt sbi po….. nd i want that knowledge

If i hv knowlege then i must hv been cleard it 🙁

Got 55 only cutoff 70

okk…don't b sad yaar u r a laborious girl. u can clr it

now wt is yr strategy for this year sbi po ?

Nt this time will plan aftr giving nicl asst. Nd fci

I hv to prep hard for reas

Nd di only .remaining section i will clr easily..

Meti tarif kam kiya kro…. :))

kadvi tarif karenge to tum gussa ho jaogi… :))

Gussa to aata h mje bt i nvr showed it on SA except one single time on a boy other then u

I nvr been angry with u… i knw

chalo humko to aap k gusse se chut mili hai :))

:)) u nd sam r my vip frnd..

nd u r my vvip frnd

It's based on archimedis principle. Simply it's answer is..

=> Rise of level= (total volume putting inside)/(area of base of the water vessel used)

=> 2(4/3 pi r^3) / pi r^2

:)) today i got best compliment of my life frm a boy…..u knw wat is that ???

wt ?

He called me daring girl……

Nd i alwz want to b fearless…

He said due to some reason. 🙂

Ok gdnt phir milenge. :))

gud nyt phir milenge chalte-chalte …:))

Plz explain Q.3?