**1.If 7^(x – y) = 343 and 7^(x + y) = 16807, what is the value of x?**

**2.The ratio between the length and the breadth of a rectangular park is 3 : 2. If a man cycling along the boundary of the park at the speed of 12 km/hr completes one round in 8 minutes, then the area of the park (in sq. m) is:**

**3.1/(1+P^(n−m))+1/(1+P^(m−n)=?**

**4.A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?**

**5. If x=(8+3√7), what is the value of (√x−1/√x) ?**

**6.(1024)^n/5×(4^2n+1)/(16)^n×(4)^n−1= ?**

**7.Today is Monday. After 61 days, it will be:**

**8.P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?**

**9.When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students**

**10.A can do a particular work in 6 days . B can do the same work in 8 days. A and B signed to do it for Rs. 3200. They completed the work in 3 days with the help of C. How much is to be paid to C?**

**ANSWERS AND SOLUTION:**

**1( A)Explanation **:7^(x – y) = 343 = 7^3

=> x – y = 3 —————————(Equation 1)

7^(x + y) = 16807 = 7^5

=> x + y = 5 —————————(Equation 2)

(Equation 1)+ (Equation 2) => 2x = 3 + 5 = 8

=> x = 8/2 = 4

**2(B)Explanation:**

Perimeter = Distance covered in 8 min. = (12000/60x 8)m = 1600 m.

Let length = 3x metres and breadth = 2x metres.

Then, 2(3x + 2x) = 1600 or x = 160.

Length = 480 m and Breadth = 320 m.

Area = (480 x 320) m2 = 153600 m^2

**3.(C)**

**4.( D)Explanation:**We have: l = 20 ft and lb = 680 sq. ft.

So, b = 34 ft.

Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft.

**5. (D)**

**6( C)**

**7(B)Explanation:**

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

After 61 days, it will be Saturday.

**8(A)Explanation :**

Amount of work P can do in 1 day = 1/15

Amount of work Q can do in 1 day = 1/20

Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60

Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15

Fraction of work left = 1 – 7/15= 8/15

**9(C)Explanation**:

Let the average weight of the 59 students be A.

So the total weight of the 59 of them will be 59*A.

The questions states that when the weight of this student who left is added, the total weight of the class = 59A + 45

When this student is also included, the average weight decreases by 0.2 kgs

59A+45/60 = A-0.2

=> 59A + 45 = 60A – 12

=> 45 + 12 = 60A – 59A

=> A = 57

**10( D)Explanation :**

Amount of work A can do in 1 day = 1/6

Amount of work B can do in 1 day = 1/8

Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24

Amount of work A + B + C can do = 1/3

Amount of work C can do in 1 day = 1/3 – 7/24 = 1/24

work A can do in 1 day: work B can do in 1 day: work C can do in 1 day

= 1/6 : 1/8 : 1/24 = 4 : 3 : 1

Amount to be paid to C = 3200 × (1/8) = 400

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Bhut naynsafi huii hai tier2 mei

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thank u ma'm for the explanations _/_

thank u ma'm for the explanations _/_

dude how r u ??

Cr???

Central region

Q5&6?