**Q1. The selling price of 10 oranges is the cost price of 13 oranges. then the profit percentage is :**

(a) 30%

(b) 10%

(c) 13%

(d) 3%

Q1. Ans. (a)

Sol.

Profit percentage = (13-10)×100/10 = 30%

**Q2. A circle of radius 8 cm has its radius decreased by 2 cm. What is the approximate percentage decrease in the area?**

(a) 25%

(b) 50%

(c) 38%

(d) 43.75%

Q2. Ans. (b)

Sol.

Original area of the circle = π (8)2 = 64 π

New area of the circle = π (6)2 = 36 π

% decrease in area = 64 π – 36 π / 64 π x 100 = 43.75%

**Q3. The sum of three consecutive odd numbers is 20 more than the smallest number. What is the middle number?**

(a) 7

(b) 9

(c) 11

(d) 5

Q3. Ans. (b)

Sol.

Let the numbers be x, x + 2 and x + 4. Then

x + (x + 2) + (x + 4) = x + 20

x = 7

So the middle number is 9.

**Q4. A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:**

(a) 600 Apples

(b) 700 Apples

(c) 500 Apples

(d) None of these

Q4. Ans. (b)

Sol.

Suppose originally he had x apples.

Then, (100 – 40)% of x = 420.

60/100 × x = 420

x = (420 x 100)/60 = 700.

**Q5. Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:**

(a) 10.8 sec

(b) 9.5 sec

(c) 7.4 sec

(d) 8.9 sec

Q5. Ans. (a)

Sol.

Relative speed = (60 + 40) km/hr = 100×5/18 = 250/9 m/ sec.

Distance covered in crossing each other = (140 + 160) m = 300 m.

Required time = 300×9/250 = 54/5 = 10.8 sec.

**Q6. When a commodity is sold for Rs 34.80, there is a loss of 25%. What is the cost price of the commodity?**

(a) 46.40

(b) 43

(c) 26.10

(d) 43.20

**Q7. The two numbers are in the ratio 2:3 and their product is 54 the sum of the numbers is?**

(a) 15

(b) 5

(c) 9

(d) 6

**Q8. In how many years a sum of money will triple itself at 8% per annum simple interest.**

(a) 25 years

(b) 37.5 years

(c) 20 years

(d) 30 years

**Q9. In how much time a train of length 120 m running at 45km/hr can cross a platform of length 230 m?**

(a) 36 sec

(b) 28 sec

(c) 14 sec

(d) 18 sec

Q9. Ans. (b)

Sol.

Crossing time = (120 + 230)/(45 * 5/18) = 28sec

**Q10. What is 6/11 of 25% of 10% of 4400?**

(a) 11

(b) 66

(c) 60

(d) 36

Q10. Ans. (c)

Sol.

6/11 of 25% of 10% 4400 = 6/11 * 25/100 * 10/100 * 4400 = 60

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