**Dear Readers, Here We are providing a quant Quiz of 15 question in accordance with the syllabus of SSC CGL. These Questions cover the topic of Speed, Distance and Time**

**Q1. A train is travelling at the rate of 45 km/hr. How many seconds it will take to cover a distance of 4/5 km?**

(a) 36 sec.

(b) 64 sec.

(c) 90 sec.

(d) 120 sec.

**Q2. An aeroplane covers a certain distance at a speed of 240 km/hour in 5 hours. To cover the same distance in 1 (2/3 )hours it must travel at a speed of:**

(a) 30 km./hr.

(b) 360 km./hr.

(c) 600 km./hr.

(d) 720 km./hr.

**Q3. A train 100 m long is running at the speed of 30 km/hr. The time (in second) in which it passes a man standing near the railway line is:**

(a) 10

(b) 11

(c) 12

(d) 15

**Q4. If a man walks 20 km at 5 km/hr. he will be late by 40 minutes. If he walks at 8km/hr. how early from the fixed time will he reach?**

(a) 15 minutes

(b) 25 minutes

(c) 50 minutes

(d) 1 (1/2) hours

**Q5. A man walking at the rate of 5 km/hr. crosses a bridge in 15 minutes. The length of the bridge (in metres) is:**

(a) 600

(b) 750

(c) 1000

(d) 1250

**Q6. A man crosses a road 250 metres wide in 75 seconds. His speed in km/hr is:**

(a) 10

(b) 12

(c) 12.5

(d) 15

**Q7. The length of a train and that of a platform are equal. If with a speed of 90 km/hr the train crosses the platform in one minute. Then the length of the train (in metres) is:**

(a) 500

(b) 600

(c) 750

(d) 900

**Q8. A train passes a 50 metres long platform in 14 seconds and a man standing on the platform in 10 seconds. The speed of the train is:**

(a) 24 km/hr

(b) 36km/hr

(c) 40km/hr

(d) 45 km/hr

**Q9. An athlete runs 200 metres race in 24 seconds. His speed (in km/hr.) is:**

(a) 20

(b) 24

(c) 28.5

(d) 30

**Q10. A car goes 10 metres in a second. Find its speed in km/hour.**

(a) 40

(b) 32

(c) 48

(d) 36

**Q11. A man riding his bicycle covers 150 metres in 25 second. What is his speed in km per hour?**

(a) 25

(b) 21.6

(c) 23

(d) 20

**Q12. A train passes two bridges of lengths 800 m and 400 m in 100 seconds and 60 seconds respectively. The length of the train is:**

(a) 80 m

(b) 90 m

(c) 200 m

(d) 150 m

**Q13. A train is 125 m long. If the train takes 30 seconds to cross a tree by the railway line, then the speed of the train is:**

(a) 14 km/hr.

(b) 15 km/hr.

(c) 16 km/hr.

(d) 12 km/hr.

**Q14.A 120 m long train takes 10 seconds to cross a man standing on a platform. What is the speed of the train?**

(a) 12 m/sec

(b) 10 m/sec

(c) 15 m/sec

(d) 20 m/sec

**Q15. A 75 metre long train is moving at 20 kmph. It will cross a man standing on the platform in**

(a) 12 seconds

(b) 14 seconds

(c) 13.5 seconds

(d) 15.5 seconds

**SOLUTIONS**

**S1. Ans.(b)**

**Sol.**Time =Distance/Speed

∴ Time =4/(5/45)=4/225 hrs

Time (sec.) =4/225×3600 = 64 sec

**S2. Ans.(d)**

**Sol**. Distance = Constant

So, speed α 1/Time

Ratio of time =5∶5/3

Ratio of time = 3 : 1

Ratioof speed = 1 : 3

1 unit → 240 km/hr

3 units →240 × 3 = 720 km/hr

So, i.e. Required speed = 720 km/hr

**S3. Ans.(c)**

**Sol.**Speed = 30 km/hr=30×5/18 m/sec

=25/3 m/sec

So, Time =D/S=100/(25/3)=12 sec

**S4. Ans.(c)**

**Sol.**Time taken at 5 km/hr=20/5

= 4 hrs

Actual time =(4-2/3)=10/3 hrs

Time taken at 8 km/hr =20/8

=5/2 hrs

Time difference =10/3-5/2=5/6 hrs

= 50 min. required time

**S5. Ans.(d)**

**Sol.**15 min =1/4 hrs

1 hrs = 5 kms

1/4 hrs. =5/4 kms

So, length of bridge =5/4 kms. = 1250 mt.

**S6. Ans.(b)**

**Sol.**S=D/T=250/75 m/sec =250/75×18/5

= 12 km/hr

**S8. Ans.(d)**

**Sol.**Distance travelled in 14 sec. = 50 + l

Distance travelled in 10 sec = l

So, speed of train

=50/(14-10) m/sec

=50/4×18/5km/hr = 45 km/hr

**S9. Ans.(d)**

**Sol.**Speed =D/T=200/24 m/sec

=200/24×18/5km/hr

= 30 km/hr

**S10. Ans.(d)**

**Sol.**Speed = 10 m/sec =10×18/5km/hr

= 36 km/hr

**S11. Ans.(b)**

**Sol**. Speed of =150/25 m/sec =6×18/5km/hr

= 21.6 km/hr

**S12. Ans.(c)**

**Sol.**Distance covered in 100 sec = 800 + l

Distance covered in 60 sec = 400 + l

So, Distance covered in 40 sec

= (800 + l) – (400 + l) = 400 mtr.

Speed → 400/40 m/sec. = 10 m/s

Distance covered in 60 sec = 10 × 60 = 600 meter

So, 400 + l = 600

⇒ l = 200 meter

**S13. Ans.(b)**

**Sol.**Speed =D/T=125/30 m/sec

=125/30×18/5km/hr

= 15 km/hr

**S14. Ans.(a)**

**Sol.**Speed =120/10 m/sec = 12 m/sec

**S15. Ans.(c)**

**Sol.**T=D/S=(75 × 18)/(20 ×5 )=27/2 sec

= 13.5 sec