**Directions (Q.1-5): Select the related letters/word/number from the given alternative.**

**1. F × H : 21 × 19 : : J × K : ?**

(a) 13 × 15

**(b) 17 × 16**

(c) 20 × 19

(d) 21 × 23

**Ans. (b)**

**21 and 19 represents the number of letters that come after F and H in alphabetical sequence in reverse order. So J= 17 and K= 16**

**2. NPRT : MNOP : : ? : GHIJ**

**(a) HJLN**

(b) FHIK

(c) FHKM

(d) FGKL

**Ans. (a)**

**In the group MNOP, the letters are shifted +1, +2, +3, +4 places in alphabetical sequence to get NPRT. Similarly, GHIJ can be converted to HJLN.**

**3. 4 : 8 : : 1 : ?**

(a) 9

(b) 3

**(c) 1**

(d) 0

**Ans. (c)**

**4**

and 8 are 2

are the next numbers in the group.

and 8 are 2

^{2}and 2^{3}respectively. So, 1^{2}and 1^{3}are the next numbers in the group.

**4. 10 : 4 : : 35 : ?**

(a) 25

(b) 13

**(c) 9**

(d) 17

**Ans. (c)**

**10/5 + 2 = 4**

**Therefore, 35/5 + 2 = 9**

**5. LIME : 43 : : JUICE : ?**

(a) 54

**(b) 53**

(c) 52

(d) 50

**Ans. (b)**

**The sum of alphabetical positions of L, I, M and E is 12+9+13+5=39.**

**So, 39+ 4(no. of letters in this word)= 43**

**The sum of alphabetical positions of J,U,I,C and E is 10+21+9+3+5=48.**

**So, 48 + 5=53.**

**6. Which one set of letters when sequentially placed at the gaps will complete the given letter series?**

**ab_accab_acc_bba_cabba_c**

**(a) bbacc**

(b) acbcc

(c) bcabb

(d) bcbba

**Ans. (a)**

**The pattern here will be ‘abb/acc/abb/acc’**

**7. If TEA is coded as 100/3, then how will you code MAT?**

(a) 120/3

**(b) 260/3**

(c) 140/3

(d) 130/3

**Ans. (b)**

**In TEA, the alphabetical positions of T, E and A are 20, 5 and 1. The positions numbers are multiplied to get the code as 100. And then divided by the number of letters(3)**

**So, The code is 100/3.**

**Similarly, MAT can be coded as 13×1×20= 260.**

**The code is 260/3**

**8. If A represents ‘×’, B represents ‘÷’, C represents ‘+’ and D represents ‘-‘’, then find the value of**

**4 A 8 D 5 C 27 B 3?**

(a) 63

(b) 25

**(c) 36**

(d) 42

**Ans. (c)**

**4 A 8 D 5 C 27 B 3**

**= 4 × 8 – 5 + 27 ÷ 3**

**= 32 – 5 + 9**

**= 36**

**Directions(Q.9-10): In a class of 45 students, the number of boys is double of the number of girls. In a class test, Abhay’s rank is 15th from the top and there are 9 girls ahead of him in rank.**

**9. How many boys are below him in rank?**

(a) 29

(b) 31

(c) 35

**(d) 24**

**Ans. (d)**

**Total students = 45**

**Let girls = x , so boys = 2x**

**x + 2x = 45**

**x = 15**

**Girls = 15**

**Boys = 30**

**Since Abhay’s rank is 15th and there are 9 girls ahead of him,**

**Students after Abhay = 45 – 15 = 30**

**No. of girls after him = 15 – 9 = 6**

**So No. of boys after him = 30 – 6 = 24**

**10. How many girls are below Abhay in rank?**

(a) 4

(b) 5

**(c) 6**

(d) 7

**Ans. (c)**

**Girls = 15**

**Boys = 30**

**Since Abhay’s rank is 15th and there are 9 girls ahead of him,**

**Students after Abhay = 45 – 15 = 30**

**No. of girls after him = 15 – 9 = 6**