Dear students, you know QUANT is a scoring portion and every chapter is important. So, we provide 15 miscellaneous questions of different topics of Quant. Solve all these quizzes every day so that you can improve your accuracy and speed. We also provide chapter wise QUANT QUESTIONS .so you can practise the chapter that takes more time to solve the QUESTIONS.

**Q1. Out of the total number of students in a college 12% are interested in sports. ¾ of the remaining number of students are interested in dancing. 10% of the total number of students are interested in singing and the remaining 15 students are not interested in any of the activities. What is the total number of students in the college?**

(a)115

(b)120

(c)125

(d)150

S1. Ans. (c)

Sol. Let total no. of students = 100

Interested in sports = 12

Interested in Dancing = 3/4 of (100-12)=66

Interested in Singing = 10

Remaining students who didn’t have interest anywhere = (100 – 12 – 66-10) = 12

According to given condition,

12 →→→ 15

Hence, 100 →→→15/12×100=125

Therefore, total no. of students = 125

**Q2. A shopkeeper sells notebooks at the rate of Rs. 457 each and earns a commission(on sp) of 4%. He also sells pencil boxes at the rate of Rs. 80 each and earns a commission(on sp) of 20%. How much amount of commission will he earn in two weeks if he sells 10 notebooks and 6 pencil boxes a day?**

(a)Rs. 4000

(b)Rs. 3909.50

(c)Rs. 3803.20

(d)Rs. 3903.20

S2. Ans. (d)

Sol. Total commission in one notebook = 4% of 457 = Rs. 18.28

Total commission in one Pencil box= 20% of 80 = Rs. 16

Hence, total commission in a day = 182.80 + 96 = Rs. 278.80

Total commission in two weeks =14 ✕ 278.80 = Rs. 3903.20

**Q3. Find the minimum number of complete years such that the simple interest on Rs. 106.25 @3% p.a. will be in exact no. of Rupees.**

(a)16 years

(b)14 years

(c)10 years

(d)12 years

**Q4. Two boys A and B start at the same time to ride from Delhi to Meerut, 60 km away. A travels 4 km an hour slower than B. B reaches Meerut and at once turns back meeting A 12 km from Meerut and at once turns back meeting A 12 km from Meerut. The speed of A was**

(a) 4 km/hr

(b) 8 km/hr

(c) 12 km/hr

(d) 16 km/hr

S4. Ans.(b)

Sol.

Let the speed of A was x km/hr.

Thus, speed of B = x +4 = km/hr

So, by the time they met, B has travelled (60 + 12) km while A has travelled (60 – 12) km.

Or, B has travelled 24 km more than A.

Since B has a margin of 4 km per hour i.e. he travelled 4 km more every hour, so it needs him 6 hours to travel 24 km more than A.

So, the required speed of A = (60 – 12)/6 km/hr.

**Q5. A trader sells an article at a loss of 8%, but when he increases the selling price of the article by Rs.164 to earns a profit of 2.25% on the cost price. If he sells the same article at Rs.1760, what is his profit percentage?**

(a) 8%

(b) 10%

(c) 7%

(d) 9%

S5. Ans.(b)

Sol.

According to question

102.25 CP – 92 CP = 164

10.25 CP = 164

CP = 1600

Profit%=160/1600×100=10%

**Q6. If the length of a rectangular field is increased by 20% and breadth is reduced by 20% the area of the rectangle becomes 288m2. What is the area of the original rectangle?**

(a) 280

(b) 205

(c) 300

(d) 285

**Q7. The equation, cos²θ=(x+y)²/4xy is only possible when,**

(a) x = – y

(b) x > y

(c) x = y

(d) x < y

**Q8. A road that is 7 m wide surrounds a circular path whose circumference is 352 m. What will be the area of the road?**

(a) 2618 m²

(b) 654.5 m²

(c) 1309 m²

(d) 5236 m²

S8. Ans.(a)

Sol. Let the inner radius = r

Then 2πr = 352 m

Then, r = 56

Then outer radius = r + 7 = 63 = R

Now, πR²-πr²= Area of road

⇒ π(R²-r² )=2618 m²

**Q9. The volume of a conical tent is 1232 cu. m and the area of its base is 154 sq. m. Find the length of the canvas required to build the tent, if the canvas is 2m in width. (Take π = 22/7)**

(a) 270 m

(b) 272 m

(c) 276 m

(d) 275 m

**Q10. A rectangular sheet of metal is 40 cm by 15 cm. Equal squares of side 4 cm are cut off at the corners and the remainder is folded up to form an open rectangular box. The volume of the box is**

(a) 896 cm³

(b) 986 cm³

(c) 600 cm³

(d) 916 cm³

**Q13. A car is being driven, in a straight line and at a uniform speed, towards the base of a vertical tower. The top of the tower is observed from the car and, in the process, it takes 10 minutes for the angle of elevation to change from 45° to 60°. After how much more time will this car reach the base of the tower?**

(a) 5(√3 + 1)

(b) 6(√3 + √2)

(c) 7(√3-1)

(d) 8(√3-2)

**Q14. A can do a job in 20 days, B in 30 days and C in 60 days. If A is helped by B and C every 3rd day. How long will it take for them to complete the job?**

(a) 12 days

(b) 4 days

(c) 15 days

(d) 18 days

S14. Ans.(c)

Sol. A → 20

B → 30

C → 60

Pattern is A, A, (A + B + C)

S.No. Days Work

1. 3 (3 + 3 + 6) = 12

5. 5 ×3 12 × 5

So, days = 15

**Q15. Two filling pipes can fill a tank in 15 hours and 12 hours respectively while a third pipe C can empty it in 20 hours when filled. If the tank is empty and all the three pipes are opened, in how much time will the tank be full?**

(a) 14 hours

(b) 10 hours

(c) 6 hours

(d) 8 hours

var pfHeaderImgUrl = ‘https://3.bp.blogspot.com/-2jjPjmwxFjQ/WYF9NjfToSI/AAAAAAAAK_E/-CGu1NOBHQYxvJ4q_9j2R6pQRI5ShdOtQCLcBGAs/s1600/Currents%2BAffairs%2BAdda%2BMobile%2BBanner.png’;var pfHeaderTagline = ‘GK%20Update%20PDF’;var pfdisableClickToDel = 0;var pfHideImages = 0;var pfImageDisplayStyle = ‘block’;var pfDisablePDF = 0;var pfDisableEmail = 1;var pfDisablePrint = 0;var pfCustomCSS = ”;var pfBtVersion=’1′;(function(){var js,pf;pf=document.createElement(‘script’);pf.type=’text/javascript’;pf.src=’//cdn.printfriendly.com/printfriendly.js’;document.getElementsByTagName(‘head’)[0].appendChild(pf)})();