Q1. 10 years ago, the ratio of age of A and B was 3: 2 and after 10 years, their ages ratio will become 5 : 4. Find the sum of their present age.

(a) 100

(b) 70

(c) 140

(d) 160

Q3. There are total 600 students in a school. Average age of boys is 12 years and of girls is 11 years while average age of all students is 11 yrs. and 3 months. Find the number of boys in the school.

(a) 130

(b) 140

(c) 150

(d) 160

Q4. Five years ago, the ratio of the ages of A and B was 2 : 3 and after 5 years it will become 5 : 7. Find their present ages.

(a) 36 yrs, 52 yrs.

(b) 37 yrs, 37 yrs.

(c) 35 yrs, 51 yrs.

(d) 45 yrs, 65 yrs.

Q5. 6 years ago, mother’s age was 18 years more than the son’s age. If the sum of their present ages is 30, what was the age of the mother 6 years back?

(a) 10 years

(b) 12 years

(c) 16 years

(d) 18 years

Q6. Six years ago, the sum of the ages of father and son was 60 years. The ratio of their present ages is 2: 1. The present age of the father is:

(a) 48 years

(b) 51 years

(c) 56 years

(d) 61 years

Q7. If C’s age is twice the average age of A, B and C. A’s age is half the average of A, B and C and if B is 5 years old, then find the average age of A, B and C is:

(a) 10 years

(b) 15 years

(c) 12 years

(d) 9 years

Q8. The respective ages of a father and his son are 50 and 16 years. In how many years will the father be thrice as old as his son?

(a) 1 year

(b) 9 years

(c) 10 years

(d) 15 years

Q9. The total ages of A, B and C at present is 90 years. Ten years ago the ratio of their ages was 5: 6:1. The present age of B is:

(a) 30 years

(b) 20 years

(c) 40 years

(d) 45 years

S9. Ans.(c)

Sol. Sum of present ages of A, B and C = 90 years

Sum of ages, 10 years ago = 60 years

And Ratio = 5 : 6 : 1

So, (5 + 6 + 1) r → 60

12r → 60

1r → 5 years

Present age of B = (30+10) years

= 40 years

Q10. The ratio of the father’s and son’s age is 7 : 4. The product of their ages is 1792. The ratio of their ages after 6 years will be:

(a) 31 : 19

(b) 8 : 5

(c) 7 : 4

(d) 5 : 8

Q11. Present age of Rahul is 8 years less than Ritu’s present age. If 3 years ago Ritu’s age was x. Also, present age of Ritu is 5 times of present age of Rahul. Find present age of Ritu

(a) 10

(b) 15

(c) 20

(d) 25

S11. Ans.(a)

Sol. According to the question,

Present age of Ritu = (x + 3)

Present age of Rahul = (x + 3 – 8)

= (x – 5)

Also,

x + 3 = 5x – 25

28 = 4x

∴ x = 7

Present age of Ritu = 10

Q12. The ratio between the ages of a father and a son at present is 5 : 3 respectively. Four years hence the ratio between the ages of the son and his mother will be 1 : 3 respectively. What is the ratio between the present ages of the father and the mother respectively?

(a) 3 : 4

(b) 5 : 4

(c) 4 : 3

(d) Can’t be determined

Q13. The age of Suhani and Navya are in the ratio of 9 : 5 respectively. After 12 years the ratio of their ages will be 13: 9. What is the difference in years between their ages?

(a) 4 years

(b) 12 years

(c) 6 years

(d) 14 years

Q14. A man’s age is 150% of what it was 10 years ago, but 75% of what it will be after 10 years. What is his present age?

(a) 25 years

(b) 30 years

(c) 35 years

(d) 40 years

Q15. The sum of the ages of a son and father is 56 yrs. After 4 yrs, the age of the father will be three times that of the son. What is the age of the son?

(a) 8 yrs

(b) 10 yrs

(c) 12 yrs

(d) 14 yrs

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