Q1. If 0<θ<90°, then (sin θ+cos θ) is:
(a) Less than 1
(b) Equal to 1
(c) Greater than 1
(d) Greater than 2
S2. Ans.(d)
Sol. In this
question we need to solve each equation one by one and then compare the
respective value.so it is true for case d.
question we need to solve each equation one by one and then compare the
respective value.so it is true for case d.
Q6. If the sides of a rectangle are increased
by 10% find the percentage increase in its diagonals.
by 10% find the percentage increase in its diagonals.
(a) 20%
(b) 10%
(c) 15%
(d) 18%
S6. Ans.(b);
Sol ∵ Percentage increase in sides = 10 %
∴ percentage increase in diagonals = 10%
Q7. Area of a rectangular field is 3584 m^2 and the length and the breadth are in the
ratio 7: 2, respectively. What is the perimeter of the rectangle?
ratio 7: 2, respectively. What is the perimeter of the rectangle?
(a) 246 m
(b) 292 m
(c) 286 m
(d) 288 m
S7. Ans.(d);
Sol. Area of rectangular = length × breadth
3584=7x×2x
x=16 m
So, perimeter =2(l+b)=2(7x+2x)
=288 m
Q8.
The length and perimeter of a rectangle are in the ratio of 5: 18. What will be
the ratio of its length and breadth?
The length and perimeter of a rectangle are in the ratio of 5: 18. What will be
the ratio of its length and breadth?
(a) 4: 3
(b) 3: 5
(c) 5: 4
(d) 4: 7
Q9. The length of a rectangle is twice its
breadth. If the length is decreased by half of the 10 cm and the breadth is increased
by half of the 10 cm, the area of the rectangle is increased by 5 sq cm more
than 70 sq cm. Find the length of the rectangle.
breadth. If the length is decreased by half of the 10 cm and the breadth is increased
by half of the 10 cm, the area of the rectangle is increased by 5 sq cm more
than 70 sq cm. Find the length of the rectangle.
(a) 30 cm
(b) 40 cm
(c) 21 cm
(d) 45 cm
Q10. A rectangle has 20 cm as its length and 200 sq cm as its area. If the area is increased by 6/5 times the original area by increasing its length only, then the perimeter of the rectangle so formed (in cm) is
(a) 72
(b) 60
(c) 64
(d) 68
