**Q1.The
cost of flooring a plot at the rate at 50 per meter square is Rs.
30,000. If ratio of length & breadth of the plot is 3:2, find the
cost of fencing at the rate of Rs. 25 per meter.**

(a) 1250 Rs

(b)4000 Rs

(c)2500Rs

(d)3600 Rs

**S1. Ans.(c)**

Sol.Area of plot = 30,000/50=600 m^2

Sol.

Let the length & breadth of the plot is 3x and 2x respectively.

So, 3x × 2x = 600

X = 10 metre

Perimeter of the plot = 2 × (30 + 20) = 100 metre.

Cost of fencing = 25 × 100 = 2500

**Q2.Perimeter
of a rectangle is 30 cm and its area is 56 sq. cm. If length and
breadth of rectangle is a equal to the height and radius of right angle
circular cylinder respectively. What is the volume of cylinder?**

(a) 1212 cm^3

(b) 1408cm^3

(c) 1418cm^3

(d) 1232cm^3

**S2. Ans.(d)**

Sol.Let the length and breadth of rectangle is l & b respectively.

Sol.

2(l + b) = 30

l + b = 15 …(i)

l × b = 56 …(ii)

Solving (i) & (ii)

l = 8

b = 7

So, height = 8 cm

Radius = 7 cm

Volume of cylinder = πr^2 h=22/7 × 8 × 7 × 7

= 1232cm^3

**Q3.The perimeter of a rhombus is 30 cm and one of its diagonal is 12 cm. Find the other diagonal of rhombus.**

(a) 9 cm

(b) 8 cm

(c) 10 cm

(d) 7 cm**Q4.A
field is 50 metre long and 30 metre wide. A path of uniform width of 10
m run around it on the inside. Find the area of the path.**

(a) 1600 cm^2

(b) 1200 cm^2

(c) 1100 cm^2

(d) 1800 cm^2

**S4. Ans.(b)**

Sol.Area of path

Sol.

= 2 × width × [Length + breadth – (2 × width)]

= 2 × 10 × [50 + 30 – 20]

= 2 × 10 × 60

= 1200 cm^2

**Q5.If the length of rectangle is increased by 20% by what percent should its width be decreased to get a same area as before.**

(a) 13.3%

(b) 25%

(c) 16.6%

(d) 33.3%**S5. Ans.(c)Sol. **Increase is length = 20% = 1/5

So decrease in width = 1/(5 + 1)=1/6

= 16.6%

**Q6.If all the sides of a square are increased by 300% its area is increased by.**

(a) 900%

(b) 1500%

(c) 1600%

(d) 1000%

**S6. Ans.(b)**

Sol.Increase in area = 2 × 300 + (300)^2/100

Sol.

= 1500%

**Q7.A
wire is bent into the shape of a square, encloses an area of 81 cm^2.
If the curie bent it into a semicircular shape, find its area.**

(a) = 77 cm^2

(b) = 154 cm^2

(c) = 616 cm^2

(d) = 84 cm^2

**S7. Ans.(a)**

Sol.Perimeter of square = 4 × √81 = 36 cm.

Sol.

Boundary of semi circle = πr+2r = 36 cm

r = 7 cm

Area of the semi circle = 1/2 πr^2

=1/2×22/7×7×7

= 77 cm^2

**Q8.A fruit seller buys oranges @ 3 oranges for Re 1 and sell them @ Rs 3 each this percentage is?**

(a) 50%

(b) 100%

(c) 200%

(d) 800%**Q9.
The height of a tower is h and angle of elevation of the top of the
tower is α. On moving a distance h/2 towards the tower, the angle of
elevation becomes β. What is the value of (cot α- cotβ)?**

(a) 1/2

(b) 1/3

(c) 3

(d) 3/2

** **

**Q11.The
base of a Pyramid is square and the length of the hypotaneous of the
base is 24√2m. If volume of the pyramid is 1728 m^3 then find the
height.**

(a) 8 m

(b) 12 m

(c) 9 m

(d) 16 m

**Q12.The**

lengths of the perpendiculars drawn from any point in the interior of

an equilateral triangle to the respective sides are p1,p2and p3. The

length of each side of the triangle is

lengths of the perpendiculars drawn from any point in the interior of

an equilateral triangle to the respective sides are p1,p2and p3. The

length of each side of the triangle is

(a) 2/√3 (p1+p2+p3 )

(b) 1/3 (p1+p2+p3 )

(c) 1/√3 (p1+p2+p3 )

(d)4/√3 (p1+p2+p3 )

**Q13.The**

marked price of a watch is Rs. 1600. The shopkeeper gives successive

discounts of 10% and x% to the customer. If the customer pays Rs. 1224

for the watch, find the value of x.

marked price of a watch is Rs. 1600. The shopkeeper gives successive

discounts of 10% and x% to the customer. If the customer pays Rs. 1224

for the watch, find the value of x.

(a) 50

(b) 10

(c) 15

(d)20

**Q14.On**

a Rs. 10000 payment order, a person has choice between three successive

discounts of 10%, 10% and 30% and three successive discounts of 40%, 5%

and 5%. By choosing the better one, he can save

a Rs. 10000 payment order, a person has choice between three successive

discounts of 10%, 10% and 30% and three successive discounts of 40%, 5%

and 5%. By choosing the better one, he can save

(a) Rs. 200

(b) Rs. 255

(c) Rs. 400

(d) Rs. 433