 # Special Quant Quiz (Advance math) SSC CGL Tier-II 2016

Q1.The
cost of flooring a plot at the rate at 50 per meter square is Rs.
30,000. If ratio of length & breadth of the plot is 3:2, find the
cost of fencing at the rate of Rs. 25 per meter.

(a) 1250 Rs
(b)4000 Rs
(c)2500Rs
(d)3600 Rs
S1. Ans.(c)
Sol.
Area of plot = 30,000/50=600 m^2
Let the length & breadth of the plot is 3x and 2x respectively.
So, 3x × 2x = 600
X = 10 metre
Perimeter of the plot = 2 × (30 + 20) = 100 metre.
Cost of fencing = 25 × 100 = 2500

Q2.Perimeter
of a rectangle is 30 cm and its area is 56 sq.  cm. If length and
breadth of rectangle is a equal to the height and radius of right angle
circular cylinder respectively. What is the volume of cylinder?

(a) 1212 cm^3
(b) 1408cm^3
(c) 1418cm^3
(d) 1232cm^3
S2. Ans.(d)
Sol.
Let the length and breadth of rectangle is l & b respectively.
2(l + b) = 30
l + b = 15            …(i)
l × b = 56            …(ii)
Solving (i) & (ii)
l = 8
b = 7
So, height = 8 cm
Volume of cylinder = πr^2 h=22/7 × 8 × 7 × 7
= 1232cm^3

Q3.The perimeter of a rhombus is 30 cm and one of its diagonal is 12 cm. Find the other diagonal of rhombus.
(a) 9 cm
(b) 8 cm
(c) 10 cm
(d) 7 cm Q4.A
field is 50 metre long and 30 metre wide. A path of uniform width of 10
m run around it on the inside. Find the area of the path.

(a) 1600 cm^2
(b) 1200 cm^2
(c) 1100 cm^2
(d) 1800 cm^2
S4. Ans.(b)
Sol.
Area of path
= 2 × width × [Length + breadth – (2 × width)]
= 2 × 10 × [50 + 30 – 20]
= 2 × 10 × 60
= 1200 cm^2

Q5.If the length of rectangle is increased by 20% by what percent should its width be decreased to get a same area as before.
(a) 13.3%
(b) 25%
(c) 16.6%
(d) 33.3%
S5. Ans.(c)
Sol.
Increase is length = 20% = 1/5
So decrease in width = 1/(5 + 1)=1/6
= 16.6%

Q6.If all the sides of a square are increased by 300% its area is increased by.
(a) 900%
(b) 1500%
(c) 1600%
(d) 1000%
S6. Ans.(b)
Sol.
Increase in area = 2 × 300 + (300)^2/100
= 1500%

Q7.A
wire is bent into the shape of a square, encloses an area of 81 cm^2.
If the curie  bent it into a semicircular shape, find its area.

(a) = 77 cm^2
(b) = 154 cm^2
(c) = 616 cm^2
(d) = 84 cm^2
S7. Ans.(a)
Sol.
Perimeter of square = 4 × √81 = 36 cm.
Boundary of semi circle = πr+2r = 36 cm
r = 7 cm
Area of the semi circle = 1/2 πr^2
=1/2×22/7×7×7
= 77 cm^2

Q8.A fruit seller buys oranges @ 3 oranges for Re 1 and sell them @ Rs 3 each this percentage is?
(a) 50%
(b) 100%
(c) 200%
(d) 800% Q9.
The height of a tower is h and angle of elevation of the top of the
tower is α. On moving a distance h/2 towards the tower, the angle of
elevation becomes β. What is the value of (cot α- cotβ)?

(a) 1/2
(b) 1/3
(c) 3
(d)  3/2

Q11.The
base of a Pyramid is square and the length of the hypotaneous of the
base is 24√2m. If volume of the pyramid is 1728 m^3 then find the
height.

(a) 8 m
(b) 12 m
(c) 9 m
(d) 16 m Q12.The
lengths of the perpendiculars drawn from any point in the interior of
an equilateral triangle to the respective sides are p1,p2and p3. The
length of each side of the triangle is

(a) 2/√3 (p1+p2+p3 )
(b) 1/3 (p1+p2+p3 )
(c) 1/√3 (p1+p2+p3 )
(d)4/√3 (p1+p2+p3 ) Q13.The
marked price of a watch is Rs. 1600. The shopkeeper gives successive
discounts of 10% and x% to the customer. If the customer pays Rs. 1224
for the watch, find the value of x.

(a) 50
(b) 10
(c) 15
(d)20 Q14.On
a Rs. 10000 payment order, a person has choice between three successive
discounts of 10%, 10% and 30% and three successive discounts of 40%, 5%
and 5%. By choosing the better one, he can save

(a) Rs. 200
(b) Rs. 255
(c) Rs. 400
(d) Rs. 433  Join India largest learning distination

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