**1.In a triangle ABC, AB + BC = 12 cm, BC + CA = 14 cm and CA + AB = 18 cm, Find the radius of the circle (in cm) which has the same perimeter as the triangle.**

(1) 5/2

(2) 7/2

(3) 9/2

(4) 11/2

**2.In DABC, PQ is parallel to BC . If AP : PB = 1 :2 and AQ = 3 cm; AC is equal to**

(1) 6 cm

(2) 9 cm

(3) 12 cm

(4) 8 cm

**3.If G be the centroid of a triangle ABC such that AG = BC, then the magnitude of ÐBGC is**

(1) 60°

(2) 90°

(3) 120°

(4) 135°

**4.Internal bisectors of angles ÐB and ÐC of a triangle ABC meet at O. If ÐBAC = 80°, then the value of ÐBOC is**

(1) 120°

(2) 140°

(3) 110°

(4) 130°

**5.In DABC,ÐA+ ÐB=65°,ÐB+ ÐC=140°, then find ÐB.**

(1) 40°

(2) 25°

(3) 35°

(4) 20°

**6.From a point P, two tangents PA and PB are drawn to a circle with centre O. If OP is equal to diameter of the circle, then ÐAPB is**

(1) 45°

(2) 90°

(3) 30°

(4) 60°

**7.From a point P which is at a distance of 13 cm from centre O of a circle of radius 5 cm. In the same plane, a pair of tangents PQ and PR are drawn to the circle. Area of quadrilateral PQOR is**

(1) 65 cm^2

(2) 60 cm^2

(3) 30 cm^2

(4) 90 cm^2

**8.Two parallel chords are drawn in a circle of diameter 30 cm. The length of one chord is 24 cm and the distance between the two chords is 21 cm. The length of the other chord is**

(1) 10 cm

(2) 18 cm

(3) 12 cm

(4) 16 cm

**9.If two equal circles whose centres are O and O’, intersect each other at the points A and B, OO’ = 12 cm and AB = 16 cm, then the radius of the circles is**

(1) 10 cm

(2) 8 cm

(3) 12 cm

(4) 14 cm

**10.AB and CD are two parallel chords of a circle such that AB = 10 cm and CD = 24 cm. If the chords are on the opposite sides of the centre and distance between them is 17 cm. then the radius of the circle is :**

(1) 11 cm

(2) 12 cm

(3) 13 cm

(4) 10 cm

**ANSWERS WITH SOLUTION ..!!!!**

**1. (2)**

**2. (2)**

**3. (2)**

**4. (4)**

**5. (2)**

**6. (4)**

**7. (2)**

**8. (2)**

**9. (1)**

**10.(3)**

**SOLUTION:**